Answer:
D) complimentary
Step-by-step explanation:
complimentary angles add up to 90 degrees
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Answer:
Step-by-step explanation:
if a person is not a hockey player, they are not a prof athlete
if a person is a hockey player, they are a prof athlete
if a person is not a prof athlete, then they r not a hockey player
Answer:
1/4
Step-by-step explanation:
3/4 + 1/4 = 4/4
Answer:
B.
Step-by-step explanation:
The answer is B. The problem says that the slope is 2 and it as the points (3,10) on its line. When looking at the graph, you can see that the line crosses at four on the y-intercept which is why four will be your constant. So, your equation in slope intercept form will become y=2x+4. With this, you can start eliminating the given answers.
You can immediately eliminate c and d because the 2 is negative when it isn't in its slope form. It leaves you with a and b.
When looking at both a and b you now have to look at what your y will become when you sinplify both of them. In choice a, the 2 multiplies with the 3 and gives you 6. Since you have to leave the y by itself you have to subtract 10 from both sides which will leave you with -4. Since your y-intercept isn't negative you know that a isnt the ansewr.
When checking b, you multiply the 2 and -3 to get -6. Since you have to leave the y by itself, you add 10 to each side and end up with 4 which is the same number that crosses the y-axis. and that is how you know it's the right answer.
