Hey! Just in case you have to show your work.
89(54x-36)+2=-3/4(-40+16x)+90x
4806x-3204+2=-3/4×4(-10+4x)+90x
4806x-3202=30-12x+90x
4806x-78x=30+3202
4728x=3232
3232÷4728=
X=404/591
The sum (addition) of t and 2 is equal to (=) 5 less than (subtraction) t
2 + t = t - 5
Lol
trouble varies directly as distance
lets say t=trouble and d=distance
t=kd
k is constant
given
when t=20, and d=400
find k
20=400k
divide by 400 both sides
1/20=k
t=(1/20)d
given, d=60
find t
t=(1/20)60
t=60/20
t=3
3 troubles
A; rate of change is the same as slope, so, using the slope formula,
, where
is the slope and
,
,
, and
are the
and
values.
Plug in
points for
and
, water level being the
and time being the
since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.
ft/hr
Answer:
the first one is ×=-2-3/5
the second one is ×=1-3y/2
hope it helps
