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In-s [12.5K]
3 years ago
12

ANYONE ABLE TO HELP??? ASAP!!!!

Mathematics
1 answer:
Artemon [7]3 years ago
5 0
I belive it c but i mit be wrong so dont mark it

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A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Learn ore about parametric equations here:

brainly.com/question/8674159

5 0
2 years ago
* PLEASE ANSWER , LOOK AT ATTACHMENTS *
dalvyx [7]

Answer:

the second option its 16

8 0
3 years ago
What would I have to do here? Somebody please help me! (Look at the bottom problem not the top)
Zinaida [17]
Alright, let's do this! If $25 is one fifth of how much the game system cost then, multiply 25 times 5. And you should get your answer. 
I hope this helps. 
8 0
2 years ago
What is P(greater than 8)?
GarryVolchara [31]

Answer:

Yes

Step-by-step explanation:

The sum must be greater than 8 it can't be 7 anyway. Sums can be 9, 10 or 12. P = (4+3+1)/36 = 3/36

3 0
1 year ago
Tameka bought 50 cans of soda ( cola, grape, and orange) to serve at a party. She has 8 more colas than grape sodas, and 3 less
Gwar [14]

Answer:

Orange = 12

Grape = 15

Cola = 23

Step-by-step explanation:

Turning this into equations you can give each soda a variable

Cola = C | Grape = G | Orange = R

Then you get:

8 + G = C

R + 3 = G

C + G + R = 50

We want to get a variable all by itself in an equation so first I'm going to put the second equation (R + 3 = G) in the first (8 + G = C) by replacing the G to get

8 + (R + 3) = C  Combine the variables 11 + R = C and put that new equation into the last equation

(11 + R) + G + R = 50    

Now plug our original second equation (R + 3 = G) into our third to get

(11 + R) + (R + 3) + R = 50    

Combine and get

14 + 3R = 50      Subtract over the 14

3R = 36              Divide by 3

Orange Sodas = 12

Our new 3rd Equation is now:   C + G + 12 = 50, subtract over 12 to get

C + G = 38

Plug either equation 1 or 2 into that one, I'll do 1

(8 + G) + G = 38

8 + 2G = 38

2G = 30

Grape Sodas = 15

Now our 3rd equation is C + 15 = 38, subtract over 15

Cola Sodas = 23

Orange = 12

Grape = 15

Cola = 23

12 + 15 + 23 = 50

7 0
2 years ago
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