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joja [24]
1 year ago
11

What is the value of x?

Mathematics
2 answers:
nalin [4]1 year ago
7 0
ANSWER: x = 27

EXPLANATION: 2 angles opposite from each other at the vortex are equal. You would set these equations equal to each other.

1. set them equal to each other.
1. (4x+7) = [5(x+l-4)].
2. Distribute the 5
2. (4x+7) = (5x-20)
3. isolate the variable (add 20 to 7)
3. 4x + 27 = 5x
4. combine the x’s (subtract 4x from 5x)
4. 27 = x

Now, to be 100% sure of your answer, fill in the x’s.

4(27) + 7 = 5[(27)-4]
108 + 7 = 5[23]
115 = 115
ki77a [65]1 year ago
3 0
X = 27
cant explain since i looked it up but im sure you can buddy
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When solving a 2 step inequality, when do you flip the inequality sign, i keep getting these questions wrong, pls help, i mark b
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You flip the signs when you are dividing by a negative value.
-2x+3>15
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Now to test this
Try putting x in the original equation when it is -5.
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3 0
3 years ago
Divide. Give the quotient and remainder.<br> 2831 divided by 25
andrew11 [14]

Answer:

113 R 6

Step-by-step explanation:

6 0
3 years ago
I need help with number 52! And I haven’t done 51
Wittaler [7]

Answer:

  51.  A/P = (2.2t +25)/(2.6t +29)

  52.  A/P for t=0 is about 0.862

         A/P for t=4 is about 0.858

Step-by-step explanation:

51. The ratio of the two given functions is ...

  r(t) = A/P

  r(t) = (2.2t +25)/(2.6t +29)

__

52. Fill in the required numbers and do the arithmetic.

  r(0) = (0 +25)/(0 +29) = 25/29

  r(0) ≈ 0.862

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  r(4) = (2.2·4 +25)/(2.6·4 +29) = 33.8/39.4

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The salary ratio is approximately flat at 0.86 over the 4-year period. It is declining slightly each year.

5 0
3 years ago
What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

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f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

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f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

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So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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