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kolbaska11 [484]
3 years ago
7

Leon Score 20 points yesterday’s game that was two more thanTwice the number of points tree scored right and solve any Quetion t

o represent the number of points try scored
Mathematics
1 answer:
Arturiano [62]3 years ago
5 0

Answer:

7 is the correct answer because

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What percentage of Priya's distance did Tyler walk​
Semmy [17]

Answer:

whats priya and tylers distance?

3 0
3 years ago
The surface area of a sphere is decreasing at the constant rate of 3π sq. cm/sec . At what rate is the volume of the sphere decr
olga nikolaevna [1]
Whooh



SA=4pir²
take derivitive
dSA/dt=8pir dr/dt

and do the volume as well
V=(4/3)pir³
dV/dt=4pir² dr/dt

we need to solve for dV/dt
to do taht we need dr/dt
so

dSA/dt=8pir dr/dt
given dSA/dt=3pi cm/sec
r=2
3pi=8pi2 dr/dt
3=16 dr/dt
3/16=dr/dt

now do the volume
dV/dt=4pir² dr/dt
r=2
dr/dt=3/16
dV/dt=4pi2² (3/16)
dV/dt=16pi(3/16)
dV/dt=3pi

nice
the volume of the sphere is decreasing at 3pi cm/sec as well
3 0
3 years ago
Mr Frank purchased 5_1/4 pounds of rocks. He used 3/5 of a pound on one aquarium. He then split the rest of the rocks between hi
riadik2000 [5.3K]

Answer:

1_11/20 pounds, or 1.55 pounds.

Step-by-step explanation:

Since at the beginning, he had 5 1/4 pounds and used 3/5, we subtract the amount of pounds. We are then left with 93/20 pounds, which he then splits among 3 containers. Dividing by three, we then get 31/20 pounds in one aquarium, or 1 11/20 pounds in each aquarium or 1.55 pounds.

6 0
3 years ago
X-30% is 12. What is X?
skad [1K]
If i'm not wrong,i think the answer is:

30%=0.3
X=0.3+12=12.3

5 0
3 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3?
Natasha2012 [34]

Answer:

x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}  are zeroes of given quadratic equation.

Step-by-step explanation:

We have been a quadratic equation:

2x^2-10x-3

We need to find the zeroes of quadratic equation

We have a formula to find zeroes of a quadratic equation:

x=\frac{b^2\pm\sqrt{D}}{2a}\text{where}D=\sqrt{b^2-4ac}

General form of quadratic equation is ax^2+bx+c

On comparing general equation with b given equation we get

a=2,b=-10,c=-3

On substituting the values in formula we get

D=\sqrt{(-10)^2-4(2)(-3)}

\Rightarrow D=\sqrt{100+24}=\sqrt{124}

Now substituting D in  x=\frac{b^2\pm\sqrt{D}}{2a} we get

x=\frac{(-10)^2\pm\sqrt{124}}{2\cdot 2}

x=\frac{100\pm\sqrt{124}}{4}

x=\frac{100\pm2\sqrt{31}}{4}

x=\frac{50\pm\sqrt{31}}{2}

Therefore, x=\frac{50+\sqrt{31}}{2},\frac{50-\sqrt{31}}{2}



5 0
3 years ago
Read 2 more answers
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