Question

A box is filled with 3 yellow cards, 2 blue cards, and 7 brown cards. A card is chosen at random from the box. What is the probability that it is a yellow or abrown card?Write your answer as a fraction in simplest form.

Answer 1

We need to find the probability of the card chosen at random is yellow or brown.

So, since there are 3 yellow cards and 7 brown cards, the total numbers of cards that are yellow or brown is:

$3+7=10$

Now, the probability that the chosen card is yellow or brown can be found by dividing the above value by the total number of cards in the box.

The total number of cards in the box is:

$3+7+2=12$

Thus, that probability is given by:

$\frac{10}{12}=\frac{10\div2}{12\div2}=\frac{5}{6}$

Therefore, the answer is:

$\frac{5}{6}$