How many chlorine (Cl) atoms would be in 4 molecules of salt (4 NaCl)?
2 answers:
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Answer:
n = -
Step-by-step explanation:
Given
(1 + n) = -
n
Multiply both sides by 6 ( the LCM of 3 and 2 ) to clear the fractions
4(1 + n) = - 3n ← distribute left side
4 + 4n = - 3n ( add 3n to both sides )
4 + 7n = 0 ( subtract 4 from both sides )
7n = - 4 ( divide both sides by 7 )
n = -