Answer:
Center is 
Step-by-step explanation:
Given: Equation of a circle is 
To find: center of the circle
Solution:
A circle is a locus of all points which are at equidistant from the fixed point (center).
Equation of a circle is of form
where
represents center of the circle and r denotes radius of the circle.
Given equation is 
![\left [ x-(-12) \right ]^2+(y-9)^2=35](https://tex.z-dn.net/?f=%5Cleft%20%5B%20x-%28-12%29%20%5Cright%20%5D%5E2%2B%28y-9%29%5E2%3D35)
Compare this equation with 
Center is 
1. distribute the 3 into the parentheses, so you would now have 6x+15=3x+4
2. combine like terms on the right side , so now you have 6x+15=7x
3. subtract the 6 from the left side so it cancels out and also subtract the 6 from the 7 so now you have 15=x
hope this answers your question !
Answer:
13
Step-by-step explanation:
4+(-3)-2*(-6)
Let us start from the left
2*(-6)= 2 times 6 , where we will have a negative sign on the result as + when multiplied by - gives - (negative)
2*(-6)=-12
4+(-3)-2*(-6) = 4+(-3)-(-12)
Now we open the bracket from the left. It the sign outside the bracket is negative the sign in the bracket will be changed
Hence
4+(-3)-(-12)= 4-3+12
Now -3 +12 we find the difference as the signs are opposite and then place the sign with the larger number
Hence -3+12=9
4-3+12=4+9 = 13