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2 years ago

6

If Fred feeds 12 horses for two weeks with 25 bales of hay, how many bales of hay does he need to feed 15 horses for two weeks?

1 answer:

Dvinal [7]2 years ago

7 0

Answer:

He needs 31.25 bales of hay to feed 15 horses for two weeks

Step-by-step explanation:

This question can be solved using a rule of three.

25 bales of hay feed 12 horses. How many feed 15 horses?

12 horses - 25 bales of hay

15 horses - x bales of hay

$12x = 25*15$

$x = \frac{25*15}{12}$

$x = 31.25$

He needs 31.25 bales of hay to feed 15 horses for two weeks

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Entre Celia y Quique suman 14€. Si Celia tuviera 1 €, tendría el doble de dinero que Quique.¿ Cuanto dinero tiene cada uno?

denpristay [2]

Answer:

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

Step-by-step explanation:

Representemos la cantidad de dinero

Celia tiene = x

Quique tiene = y

Entre Celia y Quique suman 14 €.

x + y = 14

x = 14 - y

Si Celia tuviera 1 euro, tendría el doble de dinero que Quique.

Por lo tanto,

x = 2 años

Nosotros sustituimos

2y + y = 14

3 años = 14

y = 14/3

y = 4.67 €

x = 14 € - y

x = 14 € - 4.67 €

x = 9.33 €

Por lo tanto,

La cantidad de dinero

Celia tiene = x = 9.33 €

Quique tiene = y = 4.67 €

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alexandr402 [8]

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Barb is making a necklace. She string 1 white bead,then 3 blue beads,then 1 white bead, and so on. Write the numbers for the fir

KiRa [710]

There will be 3 white beads out of the first 8.

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Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

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3 years ago