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garik1379 [7]
3 years ago
5

A forest has 800800800 pine trees, but a disease is introduced that kills \dfrac{1}{4} 4 1 ​ start fraction, 1, divided by, 4, e

nd fraction of the pine trees in the forest every year. Write a function that gives the number of pine trees remaining P(t)P(t)P, left parenthesis, t, right parenthesis in the forest ttt years after the disease is introduced.
Mathematics
1 answer:
snow_tiger [21]3 years ago
3 0

This is a perfect example of exponential decay. In this case the growth factor should be represented by a fraction, and it is! This forest, starting out with apparently ( 800? ) pine trees, has a disease spreading, which kills 1 / 4th of each of the pine trees yearly. Therefore, the pine trees remaining should be 3 / 4.

Respectively 3 / 4 should be the growth factor, starting with 800 pine trees - the start value. This can be represented as such,

P( t ) = a( b )^t - where a = start value, b = growth factor, t = time ( <em>variable quantity</em> )

____

Thus, the function P( t ) = 800( \frac{3}{4} )^t can model this problem. The forest after t years should have P( t ) number of pine trees remaining.

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Answer:

<em />

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Explanation:

The net speed or net rate for filling the 10-liters tank is equal to the speed the tap is filling less the speed the water is leaking through the hole located at the bottom of the tank:

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Thus, consiedering the tank is empty at the beginning, the time is:

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3 years ago
How far apart are the foci of an ellipse with a major axis of 34 feet and a minor axis of 16 feet?
My name is Ann [436]

The foci of an ellipse are (c,0) & (-c,0)

Where c² = a² - b²

The major axis is 34 feet

So 2a = 34

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Also minor axis is 16 feet

So 2b = 16

Dividing by 2 on both sides

b = 8

Now we know

c² = a² - b²

c² = 17² - 8² = 289 - 64 = 225

Taking square root on both sides

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Now the two foci are (15,0) & (-15,0)

Distance between these points is 15 - (-15) = 15 + 15 = 30

The distance between the two foci is 30 feet.

4 0
4 years ago
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Answer:

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