1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
harkovskaia [24]
1 year ago
15

Consider the graph of the linear function h(x) = –6 + h(x) equals negative 6 plus StartFraction 2 Over 3 EndFraction x. x. Which

quadrant will the graph not go through and why?
Mathematics
1 answer:
kifflom [539]1 year ago
8 0

The quadrant that the graph will not go through is the second quadrant.

The reason is that the slope is positive and there was a translation 6 units down

<h3>How to know the quadrant the graph will not pass</h3>

The quadrants are named in anticlockwise direction starting from the first which has x - positive and y - positive

The graph of y = 2x/3 is a graph with positive slope, moving through the third and first quadrant.

y = 2x/3 - 6 means a translation 6 units down and this pushed the line to get to the fourth quadrant

Hence the remaining quadrant that is untouched is the second quadrant

The graph is attached

learn more about graphs here:

brainly.com/question/25184007

#SPJ1

You might be interested in
Can someone help me with this please? I will mark you brainliest
lina2011 [118]

Answer:

On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vvOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.vcOn the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.On the vertical axis, place frequencies. Label this axis "Frequency".

On the horizontal axis, place the lower value of each interval. ...

Draw a bar extending from the lower value of each interval to the lower value of the next interval.

Step-by-step explanation:

6 0
3 years ago
Please help me with precal
Doss [256]

Consider the function f(x)=\sqrt{x}. This function has:

  • the domain x\in [0,\infty);
  • the range y\in [0,\infty).

If the domain of unknown function is [a,\infty), then x\ge a or x-a\ge 0. This means that you have \sqrt{x-a} as a part of needed function.

If the range of unknown function is [b,\infty), then y\ge b. This means that you have to translate function b units up and then the expression of the function is

y=\sqrt{x-a}+b.

Answer: correct choice is B.

6 0
3 years ago
A density curve for all the possible temperatures between 0°F and 40°F is a
My name is Ann [436]

Answer:

B. 0.025

Step-by-step explanation:

6 0
3 years ago
A deck builder uses 11 bags of concrete mix for every 5 deck footings. If the builder needs to build 12 deck footings, how many
juin [17]
I think it is 220 bags but i am stuipd
5 0
3 years ago
Which equation has infinitely many solutions?
liubo4ka [24]

Answer:

c

Step-by-step explanation:

i dont really have an explanation but i got it right

6 0
3 years ago
Other questions:
  • Carson evaluated 2/3÷3/4 and got an answer of 8/9. Which statement is true about his answer?
    6·1 answer
  • Define a new random variable by y = 2px. show that, as p l 0, the mgf of y converges to that of a chi squared random variable wi
    6·1 answer
  • What is the solution of this compound inequality?<br>  <br>5 &lt; 2 - 3y &lt; 14
    9·1 answer
  • Percentage of change: 30 inches to 24 inches
    10·2 answers
  • What are the terms in the expression 2x−4y+8 ?
    9·1 answer
  • An equilateral triangle has a perimeter of 90 inches. Find the area of the equilateral triangle in simplest radical form.
    12·1 answer
  • Which symbol creates a true sentence when x equals 2?<br><br><br><br> 6 • 8 – 2x _____ 6(5 + x)
    11·2 answers
  • Evaluate the expression when a=-2 and x=6. \<br><br> 4x-a
    10·1 answer
  • In a scale drawing of a painting, 1 centimeter represents 7 inches
    14·1 answer
  • The midpoint m of gh has coordinates ( -5, -4) point h has coordinates (-4, -7) find the coordinates of point g
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!