Find the length of XY to the nearest tenth of a foot
1 answer:
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Answer:
2) 4,2
Step-by-step explanation:
<u>Factor by grouping:</u>
Setting the expression equal to 0 and using the Zero Product Property, and
, which are the factors of the original polynomial.
The first thing to do is to get the graph. That's below. That is a very wicked looking graph. I'm not sure what happens at 0. I'm not sure it is continuous at 0. That's something to make a fuss over because x = 0 is one of the x intercepts.
y = - x^(2/5)(x(5/5) + 7).
y = - x^(2/5)(x + 7)
So one of the x intercepts is 0 and the other one is -7.
The reasons are known because the factors can be equated to 0. It does not look to me like there is exact symmetry. There is a local minimum however at what the graph says is (-2,-6.5 or so)
You could differentiate that to find the exact point, but you are not asked for that.
So the domain is from -∞ to zero and 0 to plus ∞ I think you have to exclude 0 even though it is an x intercept.
The graph decreases from -∞ < x < -2
It increases from -2 < x < 0
It decreases form 0< x < ∞
y = - x^(2/5)(x(5/5) + 7).
y = - x^(2/5)(x + 7)
So one of the x intercepts is 0 and the other one is -7.
The reasons are known because the factors can be equated to 0. It does not look to me like there is exact symmetry. There is a local minimum however at what the graph says is (-2,-6.5 or so)
You could differentiate that to find the exact point, but you are not asked for that.
So the domain is from -∞ to zero and 0 to plus ∞ I think you have to exclude 0 even though it is an x intercept.
The graph decreases from -∞ < x < -2
It increases from -2 < x < 0
It decreases form 0< x < ∞
9514 1404 393
Answer:
A to D is about 2087 ft
Step-by-step explanation:
For the portion of the path of interest, the sine and cosine relations apply.
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
__
AB is the adjacent side to the angle marked 33°, with hypotenuse 975 ft.
cos(33°) = AB/(975 ft)
AB = (975 ft)cos(33°) ≈ 817.70 ft
BC is the opposite side in the same triangle.
sin(33°) = BC/(975 ft)
BC = (975 ft)sin(33°) ≈ 531.02 ft
CD is the hypotenuse of the right triangle BCD. The side BC that we know is opposite the given angle, so the sine relation applies.
sin(46°) = BC/CD
CD = BC/sin(46°)
CD = (531.02 ft)/sin(46°) ≈ 738.21 ft
__
Now we know the segments of the path of interest:
A–D = AB +BC +CD
A–D = 817.70 ft + 531.02 ft + 738.21 ft = 2086.93 ft
A–D ≈ 2087 ft
_____
<em>Additional comments</em>
The attachment shows all of the segments computed working counterclockwise from A. The angles in triangle DEF are computed using the Law of Sines from sides DF and DE and angle DEF. Segments EG and GH are computed using the Law of Cosines.
When we get to points F, G, H, we find that there is some inconsistency with the locations that would be computed working clockwise using AB and angle BFA. This inconsistency shows up in an error in the 119° angle in the attached figure.
This means that segments on the back side of the route, along path EFGHA, will vary somewhat depending on how they're computed.
We assume that points B, C, F, G are collinear.
