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tekilochka [14]
3 years ago
12

For the graph, what is a reasonable constraint so that the function is at least 200?​

Mathematics
1 answer:
Anastasy [175]3 years ago
3 0

Answer:

0\leq x\leq 15

Step-by-step explanation:

I think your question missed key information, allow me to add in and hope it will fit the orginal one

<em>For the graph below, what should the domain be so that the function is at least 200?   graph of y equals minus 2 times the square of x plus 30 times x plus 200 </em>

My answer:

Given the above information, we have:

y=-2x^2+30x+200

To make  the function is at least 200, it means that:

y=-2x^2+30x+200 ≥ 200

<=> -2x^2+30x ≥ 0

<=> x(-2x+30) ≥ 0

This is the product of two numbers hence would be positive only if either both are positive or both are negative

  • Case I: Both positive

x ≥ 0 and  (-2x+30) ≥ 0

<=> 0 ≤ x ≤ 15

  • Case II: Both negative

Then we get

x\leq 0 and -2x+30\leq 0\\\\x\leq 0 and x\geq 15

This is inconsistent as a value cannot be less than 0 and greater than 15

=> our correct answer is0\leq x\leq 15

Hope it will find you well.

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