1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OLEGan [10]
2 years ago
3

Identify oxidation. increase in oxidation number. loss of electrons. decrease in oxidation number. gain of electrons

Chemistry
1 answer:
worty [1.4K]2 years ago
8 0

Oxidation is "increase in oxidation number".

A growth in oxidation number results from the losing of negatively charged electrons, whereas a reduction in oxidation number results from the gain of electrons. The result is just a rise in the oxidation number of the oxidized element and ion.

The elements in molecules and compounds were rearranged to create the products when there is a chemical reaction at the molecular level, which is where chemical changes take place. One type of chemical change is called oxidation.

Therefore, Oxidation is increase in oxidation number.

To know more about Oxidation

brainly.com/question/16976470

#SPJ4

You might be interested in
Synfuels are made from energy sources that are more plentiful than
Rashid [163]

The correct answer is oil

8 0
3 years ago
A compound of a transition metal and iodine is 56.7% metal by mass.How many grams of the metal can be obtained from 630 g of thi
erma4kov [3.2K]

Answer:

357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine

Explanation:

In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.

Given mass of sample compound = 630 g

Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;

56.7 % = 56.7/100 = 0.567

Mass of transition metal = 0.567 * 630 = 357.21 g

Therefore, the mass of the transition metal  present in 630 g of the compound is approximately 357 g

4 0
3 years ago
Which substances have high electrical conductivity?
USPshnik [31]
Copper and gold is the answer I believe
5 0
3 years ago
1. Which is an example of pure chemistry? testing the effects of lower concentrations of a drug on humans developing a cure for
motikmotik

Answer:

studying chemicals containing carbon.

Explanation:

Pure chemistry can be regarded as

branch of science that's based on conduction of basic research so that

personal knowledge can be acquired. It can be reffered to as theoretical branch of chemistry, not applied branch. It comes with curiosity about something, how and why it happens. For instance, studying chemicals containing carbon is to gain knowledge there's no applied chemistry here

7 0
3 years ago
I
dalvyx [7]

Answer:

Mixture is the answer.

8 0
4 years ago
Other questions:
  • A chlorine Cl and bromine Br atom are adsorbed on a small patch of surface (see sketch at right). This patch is known to contain
    9·1 answer
  • A __________________ forms when a cold air mass pushes into a warmer air mass.
    15·2 answers
  • What is the difference between a strong and weak acid?
    6·1 answer
  • 825 mL sample of an unknown HClO4 Solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. Wha
    15·1 answer
  • Describe some of the types of power reactors that have been designed.
    8·1 answer
  • The following chemical equation:<br>NaBr-<br>CL<br>NaCl-<br>Brg<br>Watch a video or use a hint.​
    13·1 answer
  • The difference between stager and eclipse
    10·1 answer
  • In a presentation about measuring mass, one of your classmates states, "Two objects of the same size will always have the same m
    10·2 answers
  • What is the molar mass of BE(SO4) <br> WILL GIVE BRAINLIEST ANSWER
    5·1 answer
  • What is the dependent variable in the experiment shown​
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!