Answer:
the initial concentration of SCN- in the mixture is 0.00588 M
Explanation:
The computation of the initial concentration of the SCN^- in the mixture is as follows:
As we know that

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M
So, the total milimoles of SCN^- is
= 10 × 0.05
= 0.5 m moles
The total volume in mixture is
= 45 + 10 + 30
= 85 mL
Now the initial concentration of the SCN^- is
= 0.5 ÷ 85
= 0.00588 M
hence, the initial concentration of SCN- in the mixture is 0.00588 M
Ok the ML (the 3rd number) is not legit because the ML value can only be from -L to L (the second value)
1=c 2=a 3=b
i hope these answer your questions
C-Cl bond is polar.
As Cl is more electronegative than C,
Cl pulls the shared electrons towards its side making the C-Cl bond polar.
Polar meaning C gets a partial positive charge and Cl gets a partial negative charge. Thus C-Cl bond becomes polar.
CCl4 molecule is tetrahedral.
And its shape is symmetrical.
That means its similar on all corners or all planes and it can be cut into equal halves from any plane.
C-Cl bond is polar.But the C-Cl polairty gets cancelled out as its pulled equally from all sides.
Since the molecule is symmetrical CCl4 is non polar.