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marta [7]
3 years ago
15

825 mL sample of an unknown HClO4 Solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. Wha

t is the concentration of the unknown HClO4 solution? The neutralization reaction is HClO4 (Aq) + NaOH (aq) -> H2O (l) + NaClO4 (aq)
Chemistry
1 answer:
vichka [17]3 years ago
5 0

Answer:

M_{acid}=5.484x10^{-3}M

Explanation:

Hello,

By using the following formula, which comes from the assurance of the equivalence point:

M_{acid}*V_{acid}=M_{base}*V_{base}\\M_{acid}=\frac{M_{base}*V_{base}}{V_{acid}}

We just simply compute the acid's concentration (molarity), turning out into:

M_{acid}=\frac{0.2000M*22.62mL}{825mL} \\\\M_{acid}=5.484x10^{-3}M

Best regards.

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4 0
2 years ago
Consider the reaction between hcl and o2: 4hcl(g)+o2(g)→2h2o(l)+2cl2(g) when 63.1 g of hcl are allowed to react with 17.2 g of o
Roman55 [17]
The balanced chemical reaction is expressed as:

<span>4hcl(g)+o2(g)→2h2o(l)+2cl2(g)

To determine the percent yield of the reaction, we need to calculate for the theoretical yield. This is the maximum amount of the product that can be produced from the reaction given the initial amounts of the reactants. First, we identify the limiting reactant as follows:

</span><span>63.1 g of hcl ( 1 mol / 36.46 g ) ( 1 mol O2 / 4 mol HCl) ( 32 g / mol) = 13.85 g O2 
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Therefore, the limiting reactant would be HCl. We use the value for the HCl to calculate for the theoretical yield.

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