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marta [7]
3 years ago
15

825 mL sample of an unknown HClO4 Solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. Wha

t is the concentration of the unknown HClO4 solution? The neutralization reaction is HClO4 (Aq) + NaOH (aq) -> H2O (l) + NaClO4 (aq)
Chemistry
1 answer:
vichka [17]3 years ago
5 0

Answer:

M_{acid}=5.484x10^{-3}M

Explanation:

Hello,

By using the following formula, which comes from the assurance of the equivalence point:

M_{acid}*V_{acid}=M_{base}*V_{base}\\M_{acid}=\frac{M_{base}*V_{base}}{V_{acid}}

We just simply compute the acid's concentration (molarity), turning out into:

M_{acid}=\frac{0.2000M*22.62mL}{825mL} \\\\M_{acid}=5.484x10^{-3}M

Best regards.

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Avogadro's number represents the number of units in one mole of any substance. This has the value of 6.022 x 10^23 units / mole. This number can be used to convert the number of atoms or molecules into number of moles. We calculate as follows:

237g CCl4 (1 mol / 153.81 g ) (6.022 x 10^23 molecules / 1 mol ) = 9.28x10^23 molecules
3 0
3 years ago
After he finished his work, Mendeleev predicted _____.
Alex17521 [72]

Answer:

the properties of three undiscovered elements  is the correct answer.

Explanation:

After he completed his work Mendeleev predicted the properties of the undiscovered elements.

In the year 1871, Dmitri Mendeleev predicted the detailed existence and the properties of the three elements that are undiscovered and he gained tremendous fame.

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Why are conductors better than insulators to carry electric current
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Which of the following systems has potential energy only?
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6 0
3 years ago
How many grams of F2 gas are there in a 5.00-L cylinder at 4.00 × 10^3 mm Hg and 23°C?
GuDViN [60]

Answer:

41.17g

Explanation:

We are given the following parameters for Flourine gas(F2).

Volume = 5.00L

Pressure = 4.00× 10³mmHG

Temperature =23°c

The formula we would be applying is Ideal gas law

PV = nRT

Step 1

We find the number of moles of Flourine gas present.

T = 23°C

Converting to Kelvin

= °C + 273k

= 23°C + 273k

= 296k

V = Volume = 5.00L

R = 0.08206L.atm/mol.K

P = Pressure (in atm)

In the question, the pressure is given as 4.00 × 10³mmHg

Converting to atm(atmosphere)

1 mmHg = 0.00131579atm

4.00 × 10³ =

Cross Multiply

4.00 × 10³ × 0.00131579atm

= 5.263159 atm

The formula for number of moles =

n = PV/RT

n = 5.263159 atm × 5.00L/0.08206L.atm/mol.K × 296K

n = 1.0834112811moles

Step 2

We calculate the mass of Flourine gas

The molar mass of Flourine gas =

F2 = 19 × 2

= 38 g/mol

Mass of Flourine gas = Molar mass of Flourine gas × No of moles

Mass = 38g/mol × 1.0834112811moles

41.169628682grams

Approximately = 41.17 grams.

3 0
3 years ago
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