Question

825 mL sample of an unknown HClO4 Solution requires titration with 22.62 mL of 0.2000 M NaOH to reach the equivalence point. What is the concentration of the unknown HClO4 solution? The neutralization reaction is HClO4 (Aq) + NaOH (aq) -> H2O (l) + NaClO4 (aq)

Answer 1

Answer:

$M_{acid}=5.484x10^{-3}M$

Explanation:

Hello,

By using the following formula, which comes from the assurance of the equivalence point:

$M_{acid}*V_{acid}=M_{base}*V_{base}\\M_{acid}=\frac{M_{base}*V_{base}}{V_{acid}}$

We just simply compute the acid's concentration (molarity), turning out into:

$M_{acid}=\frac{0.2000M*22.62mL}{825mL} \\\\M_{acid}=5.484x10^{-3}M$

Best regards.