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cupoosta [38]
3 months ago
13

PLEASE HELP ME!!!!!!!!!

Mathematics
1 answer:
vitfil [10]3 months ago
8 0
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

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Can some show the steps and the answer please I really need help tell me how you get it and the answer
Lana71 [14]

Answer:

Step-by-step explanation:

so this is about triangles..  sooo the following is a bit of helpful reminders that I keep on my computer to help me remember how to fit the trig functions to triangles..  I strongly suggest you copy it and keep it where you can look at it often.

Use SOH CAH TOA to recall how the trig functions fit on a triangle

SOH: Sin(Ф)= Opp / Hyp

CAH: Cos(Ф)= Adj / Hyp

TOA: Tan(Ф) = Opp / Adj

I use this anytime I run into triangles or need some help with sin or cos

now the problem , 3 ladder  10, 12, & 15 feet.   Alex wants to get to 8 feet.

the problems is also telling you that   you can use   t.....   and then , the words are cut off.. but I know they were going to say   Tan ... next.. :P

b/c Tan is how you figure out problems with the adjacent side and the opposite side.  like this problem.    Look at  TOA  above.  use that to recall how the parts fit in the formula

Tan(∅) = Opp / Adj

they give us the Opp side of 8 feet in the problem

then they also tell us the Hyp of the triangle which is each of the ladders length.  Then they ask us what is the Adj sides length?

So we also need to solve the triangle with the know hyp  (ladder length).. uggg, this problem is long. Then we can solve the dist. from the wall or Adj side length.

it's two steps, if you want to think of it that way.   You're supposed to be pretty confident with trig functions.   I'm guessing this is a trig class.. right?

let's solve for the 3 different angles that the ladders make , each going to 8 feel.  Obviously, nobody would really do this with a ladder they would just lean it against the wall . and if it's taller than where they want to climb, they would just go up part way.   so anyway,     find the 3 different angles.  

look above to see which formula to use.

I like SOH b/c it seems to have all the pieces of the triangle we want to work with.

ladder 1  ( 10')

Sin(∅) = Opp / Hyp

Sin(∅) = 8 / 10

∅ = arcSin (4/5)

[ first, yes, I just reduced the fraction, then I did the arcSin on both sides, I think you might know how to do that already ? ]

∅ = 53.13010 °

( yes, I used my calculator to find that,  calculators are okay to use when figuring out non standard angles )

ladder 2 (12')

Sin(∅) = 8/12

∅ = arcSin (2/3)

∅ = 41.81031°

ladder 3 (15')

Sin(∅) = 8/15

∅ = arcSin (8/15)

∅ = 32.230952°

now use our Tan function to find the Adjacent side which is the distance from the wall

Tan(∅)= Opp / Adj

Adj = Opp / Tan(∅)

( I did some quick algebra to move the side we want to solve for, now plug and chug all 3 angles  )

ladder 1

Adj = 8 / Tan(53.13010)

Adj = 6.0000005    

ladder 2

Adj = 8 / Tan(41.81031)

Adj = 8.94427

ladder 3

Adj = 8 / Tan(32.230952)

Adj = 12.688577

so the 10' ladder is 6 feet from the wall

the 12' ladder is 8.9 feet from the wall

the 15 foot ladder is 12.7 feet from the wall.

I really don't think that 15' ladder is going to stay on the wall.. if Alex climbs it... it's way way too far out... it will just fall straight down the wall  :/   Maybe another math problem for the forces involved  :P

5 0
2 years ago
Find the value of x.<br> If necessary, you may learn what the markings on a figure indicate.<br> 74°
marissa [1.9K]

Answer:

x = 61

Step-by-step explanation:

Left hand triangle containing 1 angle of 74

Label the other angle opposite the marked side also as 74

Find the third angle. Call it y.

y + 74 + 74 = 180           Combine like terms

y + 148 = 180                 Subtract 148 from both sides.

y = 180 - 148

y = 32

=============

Now work with the triangle on the right.

label the angle making up the right angle = z

32 + z = 90                             These two angles are complementary = 90

32 - 32 + z = 90 - 32              Subtract 32 from both sides

z = 58                                      Use 58 wherever you see z

x + x + z = 180                         Substitute

2x + 58 = 180                          Subtract 58 from both sides

2x = 122                                  Divide by 2

x = 61

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2 years ago
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3(x + 1)² = 12<br> Solve for x.
vichka [17]

Answer:

x=1, -3

Step-by-step explanation:

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2 years ago
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4. The table below shows the relationship between the time a baseball player
nekit [7.7K]

Answer:

h=5t

Step-by-step explanation:

10

3 0
1 year ago
Plz help!! I need an answer ASAP
KiRa [710]

Answer:

-5/2

Step-by-step explanation:

-5y=-2x+3

y=2/5x-3/5

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3 0
2 years ago
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