Answer:
Principal = $1,000
Rate of interest = 14% = 0.14
Time = 3 years
A = Amount or future value
P = Principal
r = rate of interest in decimals
t = time
Substitute the values in the formula
Future Value is $1481.544
Compound interest = Amount - Principal = $1481.544- $1000 = $481.544
Formula of simple interest : 
Substitute the values :
So, Simple interest = $420
Compound interest - Simple interest
= $481.544- $420
= $61.544
So, Compound Interest is $61.544 more than simple interest.
Answer:
m < FGH = 83
mPM = 139
Bottom left:
x = 16
Bottom right:
x = 5
Step-by-step explanation:
The measurement value (which is sometimes referred to simply as the measurement) is the value given by a measuring instrument and the true value is the actual value of the property being measured.
Answer:
You look very nice!
Step-by-step explanation:
it matters what you look like to yourself not how you look to others!
Answer:
m = 10 , n = 5
Step-by-step explanation:
using the cosine and tangent ratio in the right triangle and the exact values
cos45° = 
and tan45° = 1 , then
cos45° = 
= 
= ( cross- multiply )
m = 5 × = 5 × 2 = 10
-----------------------------------------
tan45° = 
= 
= 1 , then
n = 5
My answer -
<span>1. Use symbols (not words) to express quotient
2. Use exponent symbol (^) to denote exponents
3. Just write out question number, question, and choices. No need for
extra information (such as points). Also, don't leave blank lines
between choices. This extraneous that we don't need just makes your
whole question very very long, and means a lot of scrolling on our part.
4. You should only post 2 or 3 questions at a time.
1) (6x^3 − 18x^2 − 12x) / (−6x) = −x^2 + 3x + 2 ----> so much simpler to read !
2) (d^7 g^13) / (d^2 g^7) = d^(7−2) g^(13−7) = d^5 g^6 ----> much easier to read !
3) (4x − 6)^2 = 16x^2 − 24x − 24x + 36 = 16x^2 − 48x + 36
4) (x^2 / y^5)^4 = (x^2)^4 / (y^5)^4 = x^8 / y^20
5) (3x + 5y)(4x − 3y) = 12x^2 − 9xy + 20xy − 15y^2 = 12x^2 + 11xy − 15y^2
6) (3x^3y^4z^4)(2x^3y^4z^2) = (3*2) x^(3+3) y^(4+4) z^(4+2) = 6 x^6 y^8 z^6
7) 5x + 3x^4 − 7x^3 ----> Fourth degree trinomial
8) (5x^3 − 5x − 8) + (2x^3 + 4x + 2) = 7x^3 − x − 6
9) (x − 1) + (2x + 5) − (x + 3) = x + 1
10) (−4g^8h^5k^2)0(hk^2)^2 = 0 (anything multiplied by 0 = 0)
or.. (−4g^8h^5k^2)^0(hk^2)^2 = 1 (h^2 (k^2)^2) = h^2 k^4
Last question shows why it is so important to use proper symbols (such
as ^ to indicate exponents). Without such symbols, I could not tell if
the 0 was an actual number and part of multiplication, of if 0 was an
exponent of the expression preceding it.
P.S
Glad to help you have an AWESOME!!! day :)
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