All categories

1 year ago

Cos 90 - 2sin45 + 2tan180

Mathematics

1 answer:

riadik2000 [5.3K]1 year ago

4 0

Answer:

- $\sqrt{2}$

Step-by-step explanation:

cos90° - 2sin45° + 2tan180°

= 0 - ( 2 × $\frac{\sqrt{2} }{2}$ ) + 2(0)

= 0 - $\sqrt{2}$ + 0

= - $\sqrt{2}$

You might be interested in

Points A, B, and C are collinear and A is between B and C.

Katarina [22]

Answer:

"Process is shown below"

Step-by-step explanation:

Since collinear, they are on the same line. They are positioned as below:

B-----------------------A-------------------C

AB, BC, and AC's expressions are given.

To find BC, first looking at the picture, we can say:

BC = AB + AC

Putting the expressions and solving for x:

7x+5 = 4x - 3 + 5x - 16

7x + 5 = 9x - 19

19 + 5 = 9x - 7x

24 = 2x

x = 12

1. BC = 7x + 5 = 7(12) + 5 = 89

2. AB = 4x - 3 = 4(12) - 3 = 48 - 3 = 45

3. AC = 5x - 16 = 5(12) - 16 = 60 - 16 = 44

Shown

8 0

4 years ago

How would you find the values of x and y?

Ipatiy [6.2K]

If you havent learnt Sin, Cos yet, let me know, so we can try the other solutions.

6 0

4 years ago

What is the difference of the polynomials?

drek231 [11]

Answer:

In mathematics, in the area of complex analysis, the general difference polynomials are a polynomial sequence, a certain subclass of the Sheffer polynomials, which include the Newton polynomials, Solberg's polynomials, and the Stirling interpolation polynomials as special cases.

Step-by-step explanation:

6 0

3 years ago

You have a coin that is not weighted evenly and therefore is not a fair coin. Assume the true probability of getting heads when

Alexandra [31]

Answer:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=157, p=0.52)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X$

And we can use the following Excel code to find the exact answer:

"=BINOM.DIST(75,157,0.52,TRUE)"

And we got 0.1633

The other way to solve the problem is using the normal approximation

We need to check the conditions in order to use the normal approximation.

$np=157*0.52=81.64 \geq 10$

$n(1-p)=157*(1-0.52)=75.36 \geq 10$

So we see that we satisfy the conditions and then we can apply the approximation.

If we appply the approximation the new mean and standard deviation are:

$E(X)=np=157*0.52=81.64$

$\sigma=\sqrt{np(1-p)}=\sqrt{157*0.52(1-0.52)}=6.26$

We want this probability:

$P(X$

And using the continuity correction we have this:

$P(X$

We can use the z score given by this formula $Z=\frac{x-\mu}{\sigma}$ .

$P(X< 76.5)=P(\frac{X-\mu}{\sigma}< \frac{76.5-81.64}{6.26})=P(Z < -0.821)=0.206$

4 0

3 years ago

In the rhombus m<1 = 160 what are m<2 and m<3

Luba_88 [7]

The others are either 160 and 70 or 70 and 70

4 0

4 years ago