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1 year ago

Cos 90 - 2sin45 + 2tan180

Mathematics

1 answer:

riadik2000 [5.3K]1 year ago

4 0

Answer:

- $\sqrt{2}$

Step-by-step explanation:

cos90° - 2sin45° + 2tan180°

= 0 - ( 2 × $\frac{\sqrt{2} }{2}$ ) + 2(0)

= 0 - $\sqrt{2}$ + 0

= - $\sqrt{2}$

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The school day begins at 7:55 a.m. and ends at 2:40 p.m. how long are you in school?

Mademuasel [1]

Think:

7:55 a.m. is 5 minutes (5/60 hrs) before 8 a.m.;

from 8 to noon it's 4 hours, and from noon to 2:40 p.m. is 2 2/3 hours.

Thus, you're in school 5/60 hrs + 4 hrs + 2 2/3 hrs, or

6 2/3 hrs + 5/60 hrs, or 6 40/60 hrs + 5/60 hrs, or

6 45/60 hrs, or 6 3/4 hrs.

Of course there are other ways in which you could do this problem:

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2 years ago

Two lines segment that both have a midpoint at point M

AVprozaik [17]

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Step-by-step explanation:

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3 years ago

What is the range of the function graphed below?

Nadya [2.5K]

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Step-by-step explanation:

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1 year ago

Please answer quick!!!

Sidana [21]

Answer:

A. 30

Step-by-step explanation:

The interquartile range for a box and whiskers plot, is the value from the right side of the box minus the value of the left side of the box.

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3 years ago

Read 2 more answers

I need help with this question i dont understand it

RUDIKE [14]

The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
$\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2} }$
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
$\sqrt{(3-2) ^{2}+(4-3) ^{2} }$
which simplifies to
$\sqrt{(1 )^{2}+(1) ^{2} }$ which is $\sqrt{2}$
So that is the length of both MN and LM. So far our perimeter is $\sqrt{2} + \sqrt{2}=2 \sqrt{2}$
Now let's use the same formula to find out the length of one of the longer segments:
$\sqrt{(5-3) ^{2} +(3-2) ^{2} }$
which simplifies down to
$\sqrt{(2) ^{2} +(1) ^{2} }$
which is of course $\sqrt{5}$
Since we have 2 of those lengths, $\sqrt{5} + \sqrt{5}=2 \sqrt{5}$
So our perimeter is, in the end, $2 \sqrt{2}+2 \sqrt{5}$
That's the third choice down

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2 years ago