Answer:
vertical line
Step-by-step explanation:
If it is possible to draw any vertical line (a line of constant x) which crosses the graph of the relation more than once, then the relation is not a function.
Answer:
6 units
Step-by-step explanation:
I will just assume that you made a typo when typing the question when saying AB is 6√3. Here is the solution if AB = 6√2.
Since it is given that ABC is a right triangle and x labels each of the legs, the triangle is a right isoceles triangle.
Now we can use the right isoceles triangle theorem to solve the problem. This theorem states that if a leg is "x" in a right isoceles triangle, then the hypotenuse is equal to x√2.
Here, the hypotenuse is equal to 6√2. To figure out the legs, you need to solve the equation 6√2 = x√2. It is solved here:
6√2 = x√2 (Divide by √2)
x = 6
The length of the legs are 6 units.
Answer:
c) right
Step-by-step explanation:
Answer:
5(x+1) -2(y-3) = 0
Step-by-step explanation:
For a given line ax+by=c and point (h, k), a perpendicular line through the point can be written as ...
b(x-h) -a(y-k) = 0
A graphing calculator shows the point of intersection of the graphs of the two lines to be (x, y) = (-1, 3), so the line perpendicular to 2x+5y=5 through that point can be written ...
5(x+1) -2(y-3) = 0
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In the attached graph, the requested line is shown in black.
