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3 years ago

6

Three fair coins are tossed at the same time. What is the probability that all three coins will come up heads or all will come u

p tails?

1 answer:

Lostsunrise [7]3 years ago

5 0

I believe that the answer is 2 over 6

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Evaluate each logarithm. Do not use a calculator. ln ^3 square root e^4

Alona [7]

Answer:

$\large\boxed{\ln\sqrt[3]{e^4}=\dfrac{4}{3}}$

Step-by-step explanation:

$\text{Use}\\\\\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\ln a^n=n\ln a\\\\\ln e=1\\-----------\\\\\ln\sqrt[3]{e^4}=\ln e^\frac{4}{3}=\dfrac{4}{3}\ln e=\dfrac{4}{3}\cdot1=\dfrac{4}{3}$

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3 years ago

Find the measure of < 1.<br> 41<br> [?]<br> Enter

serious [3.7K]

The answer is 68°

step by step :

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3 years ago

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The amount of time a certain brand of light bulb lasts is normally distributed with a

My name is Ann [436]

If anyone has seen the answers to this question then I need please post it

6 0

3 years ago

BRAINLIEST IF CORRECT PLEASE DONT ANSWER IF YOU DONT KNOW OR REPORTED 50 POINTS I NEED MY GRADES TO BE BETTER

weqwewe [10]

Answer:

B.166 11/12

Step-by-step explanation:

To handle this problem better, we can separate the fraction and integer portions to look at the whole situation better.

First, let's only look at the integers. Anthony flew up his drone 125 feet (translating to +125), allowed it to drop 14 feet (translating to -14), and then flew it up for 55 feet (translating to +55). Hence, only considering the integers, the total change in the drone's position would be (125 - 14 + 55) feet, which equates to 166 feet.

You'd probably have already noticed this answer is quite close to B. 166 11/12 feet, but let's keep on going for now.

On the fraction part, he flew his drone up 1/2 feet, allowed it to drop 1/3 feet, and then flew it up for 3/4 feet, translating to (1/2 - 1/3 + 3/4) feet.

Hence, after making all fractions share the same denominator, that same equation would change to (6/12 - 4/12 + 9/12) feet, which equals to 11/12 feet.

Finally, the total magnitude of the drone's position would be (166 + 11/12) feet, which is equal to B.166 11/12 feet.

Hope this helped!

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3 years ago

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Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6

yan [13]

Each curve completes one loop over the interval $0\le t\le2\pi$ . Find the intersections of the curves within this interval.

$6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi$

The region of interest has an area given by the double integral

$\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta$

equivalent to the single integral

$\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta$

which evaluates to $9\pi+72$ .

8 0

3 years ago