Answer:
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Step-by-step explanation:
Population of beetles in Week 0= 6
Population of beetles in Week 7= 83
From week 0 to week 7 there are 8 weeks.
But subtracting population of week 0 from population of week 7 gives
= 83-6
= 77
After the subtraction, we have 7 weeks remaining.
Dividing the remaining population by the number of weeks remaining
=77/7
= 11
For n number of weeks, population p of beetles
P(n)= p0 + 11(n)
Where p0= population of week 0
P(n) = population of n weeks
n= number of weeks
Given:
The ratio and rates:
1. 30 ft. To 60.Ft
2. 51 males to 21 females
3. 1,500 meters in 6 seconds
4. $36 for 4 rounds of shrimp
To find:
The fraction in simple terms for the given ratio and rates.
Solution:
1. 30 ft. To 60.Ft
2. 51 males to 21 females
3. 1,500 meters in 6 seconds
4. $36 for 4 rounds of shrimp
Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
The measure of angle 1 is 75 degrees because it is a corresponding angle with the one given of 75 degrees
the measure of angle 2 is 105 degrees because it forms a supplementary angle with the one next to it that is 75 degrees. (this means they add up to 180 degrees.
Answer:
3:6, 18:4 keep exploring man!
Step-by-step explanation:
think of numbers to make them both true like ex 3 for a and 6 for b so in this case you could do 3:6
