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alexgriva [62]
1 year ago
7

_____ waves have a long wavelength and do not possess sufficient energy to kill bacterial cells, while _____ waves have a short

wavelength and can be used to sterilize a surface
Biology
1 answer:
Luden [163]1 year ago
8 0

<u>Infrared</u> waves have a long wavelength and do not possess sufficient energy to kill bacterial cells, while <u>UV</u> waves have a short wavelength and can be used to sterilize a surface.

  • When ultraviolet light, also known as ultraviolet germicidal irradiation, is released at its most effective wavelength of 253.7 nanometers (nm), it has the greatest ability to kill germs and render microbes inert (UVGI). When transmitted at wavelengths different than those recommended, germicidal efficacy declines.
  • To efficiently deliver the appropriate amount of UV radiation for the desired application, high-quality UV sterilization lamps are crucial.
  • By altering cell DNA, UV radiation sterilization efficiently renders bacteria inert.
  • Because DNA is necessary for cell reproduction, damage to the DNA's structural integrity prevents cells from multiplying and causing disease.
  • The cell absorbs the UV rays, resulting in the formation of pyrimidine dimers.
  • Instead of bonding across the double helix, this causes two nearby thymine or cytosine bases to interact with one another.

learn more about UV here: brainly.com/question/1377878

#SPJ4

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What type of heat transfer occurs when warm ocean water from the equator moves up towards the poles and cold ocean water from th
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Energy in the Ocean and Atmosphere

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A checkered hen mates with a checkered rooster. The genes for the checkered trait are codominant in both parents. What are the c
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Option D, 75%

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Let the genotype of co dominant checkered hen mates and checkered rooster be CcC and CcC

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C – is the allele for non chekered skin

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The punnet square for the cross between these two would be  

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3 out of 4 offsprings have chekered allele i.e CcCc, CcC and CcC. Thus, the probability of chekered offsprings would be 75%

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A crucial enzyme in gluconeogenesis is fructose 1,6-bisphosphatase (FBPase). It is a possible target for drugs used to treat type II diabetes. Additionally, the protein is linked to a rare genetic metabolic disorder, and certain cancer cells lack the activity of the enzyme FBPase, which encourages glycolysis and aids in the Warburg effect.

To learn more about fructose 1,6-biphosphatase enzyme click the given link

brainly.com/question/13717824

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