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8 months ago

If the molar mass of na2so4•nh2o is 304.04 g/mol, what is the hydration number 'n'?

Chemistry

1 answer:

leonid [27]8 months ago

3 0

Hydration number is 9

Given:

molar mass of na2so4•nh2o = 304.04 g/mol

To Find:

hydration number 'n'

Solution: hydration number is the number of molecules of water with which an ion can combine in an aqueous solution of given concentration.

Atomic mass of Na = 23g

S = 32g

0 = 16g

H = 1g

Molar mass of the compound is evaluated as:

2(23) +32 + 4(16) + n[2(1) +16] = 304.04

46 +32 +64 +18n = 304.04

142 +18n = 304.04

18n = 304.04 - 142

18n = 162.04

n = 9

So, hydration number is 9

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Copper has a density of 8.96 g/cm3. If a thin sheet of copper measures 5.5 cm by 5.5 cm and has a mass of 12.96 g, what is its t

balandron [24]

Thickness of cooper sheet is 0.048 cm (Approx.)

Given that;

Density of copper = 8.96 g/cm³

Measures of copper sheet = 5.5 cm × 5.5 cm

Mass of of copper sheet = 12.96 gram

Find:

Thickness of cooper sheet

Computation:

Volume = Mass / Density

Volume of cooper = 12.96 / 8.96

Volume of cooper = 1.4464

Volume of cooper = 1.45 cm³ (Approx.)

Volume of cooper sheet = 5.5 cm × 5.5 cm x Thickness

5.5 cm × 5.5 cm x Thickness = 1.45

Thickness of cooper sheet = 0.04793

Thickness of cooper sheet = 0.048 cm (Approx.)

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2 years ago

2-A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11%

aleksandrvk [35]

The molecular formula :

C₆H₁₄O₃PF

<h3>Further explanation</h3>

Given

39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine.

Required

The molecular formula

Solution

mol ratio :

C = 39.1 : 12 = 3.258

H = 7.67 : 1 = 7.67

O = 26.11 : 16 = 1.632

P = 16.82 : 31 = 0.543

F = 10.3 : 19 = 0.542

Divide by 0.542

C = 6

H : 14

O = 3

P = 1

F = 1

The empirical formula :

C₆H₁₄O₃PF

(The empirical formula)n = the molecular formula

(C₆H₁₄O₃PF)=184.1

(6.12+14.1+3.16+31+19)n=184.1

(184)n=184.1

n = 1

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2 years ago

Which orbital notation represents a noble gas in the ground state

MA_775_DIABLO [31]

In order to represent a noble gas the Orbital notation should be equal to 2, 8 or 18 for eg. 1s²

6 0

2 years ago

How many grams of NaHCO3 are needed to prepare 250 mL of 0.50 M<br> NaHCO3?

forsale [732]

Answer:

10.5g

Explanation:

First, let us calculate the number of mole of NaHCO3 present in the solution. This is illustrated below:

Volume = 250mL = 250/1000 = 0.25L

Molarity = 0.5M

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 0.5 x 0.25

Mole = 0.125 mole

Now, we shall be converting 0.125 mole of NaHCO3 to grams to obtain the desired result. This can be achieved by doing the following:

Molar Mass of NaHCO3 = 23 + 1 + 12 +(16x3) = 23 + 1 +12 +48 = 84g/mol

Number of mole of NaHCO3 = 0.125 mole

Mass of NaHCO3 =?

Mass = number of mole x molar Mass

Mass of NaHCO3 = 0.125 x 84

Mass of NaHCO3 = 10.5g

Therefore, 10.5g of NaHCO3 is needed.

6 0

2 years ago

What is the molarity of a NaOH solution when 22.14 mL of 0.105 M oxalic acid is needed to

jeka57 [31]

The molarity of the NaOH solution required for the reaction is 0.186 M

We'll begin by writing the balanced equation for the reaction

H₂C₂O₄ +2NaOH —> Na₂C₂O₄ + 2H₂O

From the balanced equation above,

The mole ratio of the acid, H₂C₂O₄ (nA) = 1

The mole ratio of the base, NaOH (nB) = 2

From the question given above, the following data were obtained:

Volume of the acid, H₂C₂O₄ (Va) = 22.14 mL

Molarity of the acid, H₂C₂O₄ (Ma) = 0.105 M

Volume of the base, NaOH (Vb) = 25 mL

<h3>Molarity of the base, NaOH (Mb) =? </h3>

MaVa / MbVb = nA/nB

(0.105 × 22.14) / (Mb × 25) = 1/2

2.3247 / (Mb × 25) = 1/2

Cross multiply

Mb × 25 = 2.3247 × 2

Mb × 25 = 4.6494

Divide both side by 25

Mb = 4.6494 / 25

Therefore, the molarity of the base, NaOH solution is 0.186 M

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2 years ago