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Korvikt [17]
1 year ago
9

If the molar mass of na2so4•nh2o is 304.04 g/mol, what is the hydration number 'n'?

Chemistry
1 answer:
leonid [27]1 year ago
3 0

Hydration number is 9

Given:

molar mass of na2so4•nh2o = 304.04 g/mol

To Find:

hydration number 'n'

Solution: hydration number is the number of molecules of water with which an ion can combine in an aqueous solution of given concentration.

Atomic mass of Na = 23g

S = 32g

0 = 16g

H = 1g

Molar mass of the compound is evaluated as:

2(23) +32 + 4(16) + n[2(1) +16] = 304.04

46 +32 +64 +18n = 304.04

142 +18n = 304.04

18n = 304.04 - 142

18n = 162.04

n = 9

So, hydration number is 9

Learn more about Hydration number here:

brainly.com/question/1313076

#SPJ4

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5. Looking at the following 5 substances, Rank them in order of increasing solubility (the ability to dissolve in water). Briefl
dalvyx [7]

Answer

:just switch the first ones around

Explanation:

i d0nt know how to explain sorry

5 0
3 years ago
30ml of 0.10 NaOh neutralized 25.0ml of HCL determine the concentration of the HCL? PLEASE HELP ME ASAP
Contact [7]
The equation is one to one so you can use M1V1=M2V2
so
(30ml)(.10M)=(25ml)(x)
x= .12M
6 0
3 years ago
5. A shiny, gold-colored bar of metal weighing 57.3 g has a volume of 4.7 cm 3 . Is the bar of metal pure
agasfer [191]

1. The bar of metal is not pure gold.

2. The volume of 50.0 g of air is 42,016 mL.

3. The mass of the pure aluminum is 135 g.

4. The light beam's wavelength in meters is 475 x  10^{-9 m.

<h3>What is density?</h3>

The density of a substance is the ratio of the mass of the substance and its volume.

Density = mass/volume.

For the first problem: mass = 57.3 g, volume = 4.7 cm3

Density of the metal = 57.3/4.7

                                   = 12.19 g/cm3

The density of gold is 19.3 g/cm3. Thus, the bar of metal is not pure gold.

For the second problem: density = 1.19 x 10^{-3 g/ml, mass = 50.0 g

Volume = mass/density

                 = 50/1.19 x 10^{-3

                      = 42,016 ml

The volume of 50.0 g of air is 42,016 mL.

For the third problem: density = 2.70 g/ml, volume = 50.0 ml.

Mass = density x volume

                 = 2.70 x 50

                       = 135 g

The mass of the pure aluminum is 135 g.

Lastly:

nano = 10^{-9

475 nm = 475 x  10^{-9 m

The light beam's wavelength in meters is 475 x  10^{-9 m.

More on density can be found here: brainly.com/question/15164682

#SPJ1

6 0
1 year ago
Which of these following have a positive charges
Over [174]
Talking about ions, a cation has a positive charge. That means a positive charge is gained by an atom that gives out electrons. 
7 0
3 years ago
500 mL of He at 300 K is heated to 450 K. Find V2
ruslelena [56]

Answer:

V2 = 0.75 L

Explanation:

assumin ideal gas:

  • PV = RTn

∴ T1 = 300K

∴ V1 = 0.500 L

∴ T2 = 450 K

⇒ V2 = ?

assuming P, n constant:

⇒ PV1 = RT1n

⇒ V1/T1 = Rn/P = K..........(1)

⇒ V2/T2 = RN/P = K..........(2)

(1) = (2):

⇒ V1/T1 = V2/T2

⇒ V2 = (V1/T1)T2

⇒ V2 = (0.500 L/300 K)(450 K)

⇒ V2 = 0.75 L

8 0
3 years ago
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