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DENIUS [597]
1 year ago
11

A student is trying to solve the system of two equations given below: equation p: y z = 6 equation q: 3y 4z = 1 which of these i

s a possible step used in eliminating the y-term? (y z = 6) ⋅ 4 (3y 4z = 1) ⋅ 4 (y z = 6) ⋅ −3 (3y 4z = 1) ⋅ 3
Mathematics
1 answer:
Vadim26 [7]1 year ago
6 0

<u>Option C is correct </u><u>(y + z = 6) ⋅ −3</u>

What is a linear equation in math?

  • A linear equation only has one or two variables.
  • No variable in a linear equation is raised to a power greater than 1 or used as the denominator of a fraction.
  • When you find pairs of values that make a linear equation true and plot those pairs on a coordinate grid, all of the points lie on the same line.

As per the statement -

A student is trying to solve the system of two equations given below:

Equation P:   y + z = 6              ....[1]

Equation Q:  3y + 4z = 1           ....[2]

Multiply the equation [1] by -3 to both sides we have;

-3 .( y + z = 6 ) ⇒ -3y -3z = -18..........(3)

                   

Add equation [2] and [3] to eliminate the y-term;

z = -17

Therefore, the  possible step used in eliminating the y-term is, (y + z = 6) ⋅ −3

Learn more about linear equation

brainly.com/question/11897796

#SPJ4

<u>The complete question is -</u>

A student is trying to solve the system of two equations given below: Equation P: y + z = 6 Equation Q: 3y + 4z = 1 Which of these is a possible step used in eliminating the y-term?

(y + z = 6) ⋅ 4

(3y + 4z = 1) ⋅ 4

(y + z = 6) ⋅ −3

(3y + 4z = 1) ⋅ 3

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4 0
3 years ago
write an equation in slope intercept form of a line that passes through the point (14,8) and is (a) parallel (b) perpendicular t
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Slope-intercept form:

y = mx + b       "m" is the slope, "b" is the y-intercept (the y value when x = 0)


First find the slope of the line that passes through (4,9) and (-3,6).

Use the slope formula and plug in the two points:

m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

m=\frac{6-9}{-3-4}

m=\frac{-3}{-7} =\frac{3}{7}



A.) For lines to be parallel, their slopes have to be the same.

Since the given line's slope is 3/7, the parallel line's slope is also 3/7


y = 3/7x + b    To find "b", plug in the point (14,8) into the equation

8 = 3/7(14) + b

8 = 42/7 + b

8 = 6 + b    Subtract 6 on both sides

2 = b


y=\frac{3}{7}x+2



B.) For lines to be perpendicular, their slopes have to be the opposite/negative reciprocal (flipped sign and number)

For example:

slope is 3

perpendicular line's slope is -1/3

slope is -2/3

perpendicular line's slope is 3/2


Since the given line's slope is 3/7, the perpendicular line's slope is -7/3

y = -7/3x + b    Plug in (14, 8) to find "b"

8 = -7/3(14) + b

8 = -98/3 + b   Add 98/3 on both sides

8 + 98/3 = b       Make the denominators the same

24/3 + 98/3 = b

122/3 = b


y=-\frac{7}{3}x+\frac{122}{3}

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3 years ago
How to rewrite 2+2+2+2+2 into a multiplication problem?
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Answer:

2 x 5

Step-by-step explanation:

Think of it as "the value 2 is being added together 5 times" being added together so it could be written as 2 times 5.

5 0
3 years ago
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Math surface area help plz
Stolb23 [73]
So, use the formula:

A = .5(8)(27)

A = 108
3 0
3 years ago
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Can you find what each of the answers are
Ksju [112]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

1. Find Angle A :

  • x  + 24 = 3x

  • 3x - x =   2 4

  • 2x = 24

  • x = 12

Angle A :

  • 3x

  • 3 \times 12

  • 36 \degree

2. Find Angle B :

  • 10x - 27 = 7x

  • 10x - 7x = 27

  • 3x = 27

  • x = 9

Angle B :

  • 10x - 27

  • (10 \times 9) - 27

  • 90 - 27

  • 63 \degree

Find Angle C :

  • 5x + 1 = 6x  - 13

  • 6x - 5 x =  1 + 13

  • x = 14

Angle C :

  • 5x + 1

  • (5 \times 14) + 1

  • 70 + 1

  • 71 \degree

Find Angle D :

  • 6x  +  3 = 4x + 39

  • 6x - 4x = 39  -  3

  • 2x = 36

  • x = 18

Angle D :

  • 4x + 39

  • (4 \times 18) + 39

  • 72 + 39

  • 111\degree

And it's given :

  • 36° = Angle A = B

  • 63° = Angle B = A

  • 71° = Angle C = H

  • 111° = Angle D = E

Therefore, the answer will be " BAHE "

4 0
3 years ago
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