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Reika [66]
3 years ago
9

Writs a doubles plus one fact for the sum of 7

Mathematics
1 answer:
lbvjy [14]3 years ago
3 0
I think that 3 (3•2+1=7)
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- 6 (1+3)=<br> Propiedad distributiva
astraxan [27]
Hi! So what you’re gonna do is multiple everything in the parentheses by what is in front of the parentheses. In this case it is -6!

-6•1=-6
-6•3=-18

-6+-18=-24

Please give brainliest!
4 0
3 years ago
Need help quick ASAP!!!!!
iris [78.8K]
4 Bus stops... I hope this helped
8 0
3 years ago
Read 2 more answers
Please help me I’m so lost !!!!
Tasya [4]

Answer:

4095

Step-by-step explanation:

\sum _{n=1}^63\left(4^{n-1}\right)\:

\sum _{n=1}^63\cdot \:4^{n-1}

Compute general progression:

\frac{3\cdot \:4^{\left(n+1\right)-1}}{3\cdot \:4^{n-1}}=4

r=4\\

a_1=3\cdot \:4^{1-1}

a_1=3

nth term is computed by:

r=4,\:a_n=3\cdot \:4^{n-1}

plug in the values n=6,\:\spacea_1=3,\:\spacer=4:

=3\cdot \frac{1-4^6}{1-4}

=4095

5 0
3 years ago
Samantha wants to move into an apartment when she begins school in the fall. Right now she
kompoz [17]

Answer:

she should set up a budget on how much she makes

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
There are premium tickets costing $99 each and rest are regualr tickets costing $25 each. A pile of 120 tickets have a total val
polet [3.4K]

Answer:

There are 38 premium tickets and 82 regular tickets in a pile.

Step-by-step explanation:

Given,

Total number of tickets = 120

Total amount = $5812

Solution,

Let the number of premium tickets be x.

And the number of regular tickets be y.

Total number of tickets is the sum of total number of premium tickets and  total number of regular tickets.

So the equation can be written as;

x+y=120\ \ \ \ \ equation\ 1

Again,total amount  is the sum of total number of premium tickets multiplied by cost of each premium ticket and  total number of regular tickets multiplied by cost of each regular ticket.

So the equation can be written as;

99x+25y=5812\ \ \ \ equation\ 2

Now We will multiply equation 1 by 25 we get;

x+y=120\\25(x+y)=120\times25\\25x+25y= 3000 \ \ \ \ equation\ 3

Now Subtracting equation 3 from equation 2 we get;

(99x+25y)-(25x+25y)=5812-3000\\\\99x+25y-25x-25y=2812\\\\74x=2812\\\\x=\frac{2812}{74}=38

We will now substitute the value of x in equation 1 we get;

x+y=120\\38+y=120\\y=120-38\\y=82

Hence There are 38 premium tickets and 82 regular tickets in a pile.

3 0
3 years ago
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