Midpoint of (x1,y1) and (x2,y2) is
so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is
the midpoint is (3.5,1)
so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is
the midpoint is (3.5,1)
A line passes through the point (7, 3. and has a slope of 2. Write an equation for this line.
1 answer:
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The position vector of P and Q is P = ( 6 i -3j +9k ) , Q = ( 3i -6 j -3k) , the coordinates of R is ( 5 , -4 , 2)
<h3>What is a vector ?</h3>A vector is an object with both mass and magnitude.
It is given that
The coordinates of
P (6, -3,9 ) and Q (3, -6, -3)
point R divides line PQ internally in the ratio 1:2.
The position vectors of P, Q and R is given by p, q and r respectively.
The position vector of P and Q in terms of i, j, k is is
P = ( 6 i -3j +9k ) , Q = ( 3i -6 j -3k)
The magnitude of P =
|p| = 11.224
The magnitude of Q =
|q| = 7.348
The coordinate of R is
if a point (x,y,z) divides the line joining the points (x₁,y₁) ) and (x₂ ,y₂) in the ratio m:n, then
( x, y, z ) =
The m : n = 1 : 2
(x,y,z) =
(x,y,z) = 5 , -4 , 2
Therefore the coordinates of R is ( 5 , -4 , 2)
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