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makvit [3.9K]
4 years ago
12

What is the midpoint coordinates of segment HX H(13,8) X(-6,-6)

Mathematics
1 answer:
Setler79 [48]4 years ago
7 0
Midpoint of (x1,y1) and (x2,y2) is

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

so the midpoint of HX is the mdpoint of (13,8) and (-6,-6)
which is

(\frac{13-6}{2},\frac{8-6}{2}=
(\frac{7}{2},\frac{2}{2}=
(3.5,1)

the midpoint is (3.5,1)
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