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1 year ago

How many lines can be drawn through points J and K?

Mathematics

2 answers:

vitfil [10]1 year ago

6 0

We need some sort of image of further elaboration to answer this. Sorry!

Harrizon [31]1 year ago

4 0

Answer:

show the image because we cant answer it if there's no picture or image

Step-by-step explanation:

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Find the angles of a, b, c and d in the diagram

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Dawson practices soccer for 30 minutes each weekday. The expression 30x can be used to find the total number of minutes Dawson h

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Given the following trigonometric ratio, enumerate the meaning ratio

Likurg_2 [28]

Answer:

The trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

Step-by-step explanation:

From Trigonometry we know the following definitions for each trigonometric ratio:

Sine

$\sin \theta = \frac{y}{h}$ (1)

Cosine

$\cos \theta = \frac{x}{h}$ (2)

Tangent

$\tan \theta = \frac{\sin \theta}{\cos \theta} = \frac{y}{x}$ (3)

Cotangent

$\cot \theta = \frac{\cos \theta}{\sin \theta} = \frac{x}{y}$ (4)

Secant

$\sec \theta = \frac{1}{\cos \theta} = \frac{h}{x}$ (5)

Cosecant

$\csc \theta = \frac{1}{\sin \theta} = \frac{h}{y}$ (6)

Where:

$x$ - Adjacent leg.

$y$ - Opposite leg.

$h$ - Hypotenuse.

The length of the hypotenuse is determined by the Pythagorean Theorem:

$h = \sqrt{x^{2}+y^{2}}$

If $y = AC$ and $x = BC$ , then the trigonometric ratios are presented below:

$\sin \theta = \frac{AC}{\sqrt{AC^{2} + BC^{2}}}$

$\cos \theta = \frac{BC}{\sqrt{AC^{2} + BC^{2}}}$

$\cot \theta = \frac{BC}{AC}$

$\sec \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{BC}$

$\csc \theta = \frac{\sqrt{AC^{2}+BC^{2}}}{AC}$

6 0

3 years ago

Hugo is designing a frame as shown at the right. The frame has a width of x inches all the way around. Write. an expression that

Cloud [144]

The expression which shows the total area of the picture and frame is $x^{2} +72x$ +320.

Given that the width of the frame is x ,length horizontally be 20 inches and vertically be 16 inches.

We are required to find the expression which shows the total area of the picture and frame.

Expression is basically a combination of numbers, symbols, coefficients, determinants, indeterminants,etc. and are mostly not found in equal to form.

Since we are given that the width of the frame be x, So,the are of only frame will be :

Area of frame=20*x*2+16*x*2+x*x

=40x+32x+ $x^{2}$

= $x^{2}$ +72x

Area of picture=20*16=320 $inches^{2}$

The expression which shows the total area of the picture and frame is $x^{2} +72x$ +320.

Hence the expression which shows the total area of the picture and frame is $x^{2} +72x$ +320.

Learn more about expression at brainly.com/question/723406

#SPJ9

6 0

1 year ago