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1 year ago

HOW MANY DIFFERENT COMMITTEES CAN BE FORMED FROM 4 TEACHERS AND 20

Mathematics

1 answer:

Daniel [21]1 year ago

4 0

Answer:

6840

Step-by-step explanation:

multiply combinations

n!/(r!(n − r)!)

n choose r

n (objects) = |n

r (sample) = r

(4 teachers, CHOOSE 2)*(20 students, CHOOSE 3)

C(4,2) times C(20,3) =

C(n,r)=?

C(n,r) = C(4,2)

4! / (2!(4-2)!)

4! /2! x 2!

= 6

C(n,r)=?

C(n,r) = C(20,3)

20! / (3!(20-3)!)

20! / 3! x 17!

= 1140

6 * 1140 = 6840

alegbracom Edwin McCravy

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