Question

HOW MANY DIFFERENT COMMITTEES CAN BE FORMED FROM 4 TEACHERS AND 20

Answer 1

Answer:

6840

Step-by-step explanation:

multiply combinations

n!/(r!(n − r)!)

n choose r

n (objects) = |n

r (sample) = r

(4 teachers, CHOOSE 2)*(20 students, CHOOSE 3)

C(4,2) times C(20,3) =

C(n,r)=?

C(n,r) = C(4,2)

4! / (2!(4-2)!)

4! /2! x 2!

= 6

C(n,r)=?

C(n,r) = C(20,3)

20! / (3!(20-3)!)

20! /  3! x 17!

= 1140

6 * 1140 = 6840

alegbracom Edwin McCravy