AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9

Therefore AB is 9 cms.
Answer:
Here you are. I hope this helps.
1 = sin²0 + cos²0
sin²0 = 1 - cos²0
sin²0 = 1 - 11/36
sin²0 = 25/36
sin 0 = 5/6 or -5/6
In the first quadrant, the values for sin, cos and tan are positive.
sin0 = 5/6
Step-by-step explanation:

Apply Quoteint of Powers. Divide the intergers. serpately.
Note that Quotient of Powers is

So the answer is

The answer is

or
