Which equation represents the line that is perpendicular to and passes through (-6,-9)?
1 answer:
Answer:
y = -9
Step-by-step explanation:
Complete question;
Which equation represents the line y = 1/4 that is perpendicular to and passes through (-6,-9)?
The equation of the line in point slope form is y-y0 = m(x-x0)
Given the equation y = 1/4, the slope of the line is zero
Substitute the slope and the point into the formula;
y -(-9) = 0(x-(-6)
y + 9 = 0
y = -9
Hence the required equation is y = -9
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Answer: 10
2AX=BD
2(3y-5)=5y
6y-10=5y
add 10 to each side 6y+10-10=5y+10
6y=5y+10
subtract 5y from each side 6y-5y=5y-5y+10
6y-5y=y
y=10
your answer would be (2,3)
We have that
using a graph tool
see the attached figure
The horizontal asymptote of this function is at <span>y=3</span><span>.
So,
the range of this function is from </span><span>
(−∞,3<span>
)</span></span>
Step-by-step explanation:
yes that's true
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then
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Step-by-step explanation: