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Anon25 [30]
2 years ago
6

HEY PLEASE HELP ASAP

Mathematics
2 answers:
Sladkaya [172]2 years ago
7 0

{ \qquad\qquad\huge\underline{{\sf Answer}}}

Let's simplify ~

\qquad \sf  \dashrightarrow \:  \cfrac{5}{y - 1}  +  \cfrac{3}{y - 8}

\qquad \sf  \dashrightarrow \:  \cfrac{5(y - 8) + 3(y - 1)}{(y - 1)(y - 8)}

\qquad \sf  \dashrightarrow \:  \cfrac{5y -40 + 3y - 3}{y {}^{2}  - y - 8y  + 8}

\qquad \sf  \dashrightarrow \:  \cfrac{8y -43}{y {}^{2}  - 9y  + 8}

LekaFEV [45]2 years ago
5 0

Answer:

\dfrac{8y-43}{(y-1)(y-8)}

Explanation:

\rightarrow \dfrac{5}{y-1} +\dfrac{3}{y-8}

make the <u>denominators</u> similar

\rightarrow \dfrac{5(y-8)}{(y-1)(y-8)} +\dfrac{3(y-1)}{(y-8)(y-1)}

<u>Join</u> both the fraction

\rightarrow \dfrac{5(y-8)+3(y-1)}{(y-1)(y-8)}

<u>simplify</u> the expression

\rightarrow \dfrac{5y-40+3y-3}{(y-1)(y-8)}

\rightarrow \dfrac{8y-43}{(y-1)(y-8)}

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