Factor ab + bc + b 2 + ac. b(a + b)(b + c) (a + c)(b + c) (a + b)(b + c). ???
2 answers:
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Let the first number be = x
Let the second number which is consecutive be = x+1
As given, the product of two consecutive square numbers is 144
Square rooting both sides we get
or
Neglect the negative value so we get x=3
Hence, one number is 3 and the consecutive number is = 3+1=4
The square of the numbers are 9 and 16.
Dividing a number by the ratio 3:2 means dividing into 3+2 = 5 parts
Let (0, 0) be (x₁, y₁) and (3, 6) be (x₂, y₂)
Find one part of the share for each axes, we do
Then multiplying the one part back into 3: 2, we have
for the x - axis ⇒ (3×0.6) : (2×0.6) = 1.8: 1.2
for the y - axis ⇒ (3×1.2) : (2×1.2) = 3.6: 2.4
The coordinate that divides the segment into 3 parts and 2 parts is (1.8, 3.6)
Correct answer: A
Let (0, 0) be (x₁, y₁) and (3, 6) be (x₂, y₂)
Find one part of the share for each axes, we do
Then multiplying the one part back into 3: 2, we have
for the x - axis ⇒ (3×0.6) : (2×0.6) = 1.8: 1.2
for the y - axis ⇒ (3×1.2) : (2×1.2) = 3.6: 2.4
The coordinate that divides the segment into 3 parts and 2 parts is (1.8, 3.6)
Correct answer: A