$\sf a + b + c = 0\\abc \neq 0\\\\ \frac{a^2}{bc} + \frac{b^2}{ac} + \frac{c^2}{ab} = \frac{a^3+b^3+c^3}{abc} \\\\\sf Formula: \\a^3 + b^3 + c^3 = (a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc\\\\\frac{a^3+b^3+c^3}{abc}= \frac{(a + b + c) (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf However, ~a+b+c = 0. ~So:\\\\\frac{0 (a^2 + b^2 + c^2- ab - bc - ca) + 3abc}{abc}\\\\\sf Multiply~ anything ~by~ 0, ~and~ you ~get~ 0. ~So~ simplifying:\\\\\frac{3abc}{abc} = \boxed{3}$

Your final answer is 3.

3 0

3 years ago

The product of 45/87 and --9/10 is

grandymaker [24]

Answer:

0.4655172413793

Step-by-step explanation:

45/87 ×-9/10 i

405÷870

0.4655172413793

7 0

3 years ago

Please help me guys 20 points<br><br> How do you do e

sineoko [7]

You add them all up

6 0

3 years ago

Read 2 more answers

C. When the center of Earth is 2 x 10^11meters from the center of Mars, the force of gravity

tresset_1 [31]

Answer:

When the center of Earth is 2 × 1011 meters from the center of Mars, the force of gravity between the two planets is about 64.32 × 1014 newtons. The mass of Earth is about 6 × 1024 kilograms, and the mass of Mars is about 6.4 × 1023 kilograms. Using these values, estimate the gravitational constant.

6 0

3 years ago