Find the m of
1 answer:
Both of these problems will be solved in a similar way, but with different numbers. First, we set up an equation with the values given. Then, we solve. Lastly, we plug into the original expressions to solve for the angles.
[23] ABD = 42°, DBC = 35°
(4x - 2) + (3x + 2) = 77°
4x+ 3x + 2 - 2 = 77°
4x+ 3x= 77°
7x= 77°
x= 11°
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ABD = (4x - 2) = (4(11°) - 2) = 44° - 2 = 42°
DBC = (3x + 2) = (3(11°) + 2) = 33° + 2 = 35°
[24] ABD = 62°, DBC = 78°
(4x - 8) + (4x + 8) = 140°
4x + 4x + 8 - 8 = 140°
4x + 4x = 140°
8x = 140°
8x = 140°
x = 17.5°
-
ABD = (4x - 8) = (4(17.5°) - 8) = 70° - 8° = 62°
DBC =(4x + 8) = (4(17.5°) + 8) = 70° + 8° = 78°
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Answer:
For 124 chirps per minute the temperature is 68 ºF.
For 68 chirps per minute the temperature is 54 ºF.
Step-by-step explanation:
Linear functions are those whose graph is a straight line. A linear function has the following form
b is the constant term or the y intercept. It is the value of the dependent variable when x = 0.
m is the coefficient of the independent variable. It is also known as the slope and gives the rate of change of the dependent variable.
We know that
- At 104 chirps per minute, the temperature is 63 ºF.
- At 176 chirps per minute, the temperature is 81 ºF.
This information can be converted to Cartesian coordinates (x, y). Where x = the number of chirps per minute and y = the temperature in ºF.
To find a linear function that let us find the outside temperature from how fast crickets chirp we must:
- Find the slope:
- Find the equation:
Solving for b
Therefore, the linear function is
Now, using this linear function we can know the temperature when we know the chirps per minute:
For 124 chirps per minute the temperature is:
For 68 chirps per minute the temperature is: