<u>Given</u>:
The base of each triangular base is 42 m.
The height of each triangular base is 20 m.
The sides of the triangle are 29 m each.
The height of the triangular prism is 16 m.
We need to determine the surface area of the triangular prism.
<u>Surface area of the triangular prism:</u>
The surface area of the triangular prism can be determined using the formula,
where b is the base of the triangle,
h is the height of the triangle,
s₁, s₂ and s₃ are sides of the triangle and
H is the height of the prism.
Substituting the values, we get;
Thus, the surface area of the triangular prism is 2440 m²
Answer:
The weight of the water in the pool is approximately 60,000 lb·f
Step-by-step explanation:
The details of the swimming pool are;
The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet
The depth of the pool = 5 feet
The density of the water in the pool = 60 pounds per cubic foot
From the question, we have;
The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g
The volume of water in the pool = Cross-sectional area × Depth
∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³
Acceleration due to gravity, g ≈ 32.09 ft./s²
∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N
266,196.089 N ≈ 60,000 lb·f
The weight of the water in the pool ≈ 60,000 lb·f
Answer:
The 2nd, 3rd, and 8th choice
Step-by-step explanation:
Answer:
R=9
Step-by-step explanation:
In the equation, replace k with 3.
R=5(3)-6
Multiply.
R=15-6
Subtract
R=9
I hope this helps!
