Answer:
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Step-by-step explanation:
In this question we have to test an hypothesis.
The null and alternative hypothesis are:
The significance level is assumed to be 0.01.
The sample of size n=80 gives a proportion of p=61/80=0.7625.
The standard deviation is:
The statistic z is then
The P-value is
The P-value (0.003) is smaller than the significance level (0.010), so the effect is significant. The null hypothesis is rejected.
There is strong evidence that less than 87% of the orders are delivered in less than 10 minutes.
Decision rule: Reject the null hypothesis if (P-value < level of significance)
Test statistic z=-2.70
Decision: Reject the null hypothesis (0.003<0.010)
Average temperature change can be found through the equation
Avg Temp change per hour=Total temperature change ÷ Total time
=84÷12
=7
Since the temperature was decreasing, make the 7 negative -7
Hope this helps!
Answer:
1, 2, 4, 5, 8, 10, 20, 40
Step-by-step explanation:
40 =
1 * 40
2 * 20
4 * 10
5 * 8
Factors: 1, 40, 2, 20, 4, 10, 5,8
Factors least to greatest: 1, 2, 4, 5, 8, 10, 20, 40
Hope this helps :)
X=weekly allowance
x/2=money saved (= money spent).
We can suggest this equation:
x/2+4=12
lowest common multiple=2
x+8=24
x=24-8
x=16
Answer: her weekly allowance is $16.
The answer would be p= -2
To check it:
-2(5(-2) - 3) = 26
-2(-10-3) = 26
-2(-13) = 26
26 = 26