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jekas [21]
1 year ago
15

► Factor. 1) 9y² - (2x - y)² =

Mathematics
1 answer:
Colt1911 [192]1 year ago
5 0

Answer:

( 4y + 4x ) ( 2y - x )

Step-by-step explanation:

→ Expand bracket

(2x - y)² = (2x - y) (2x - y) = 4x² - 4xy + y²

→ Rewrite

9y² - ( 4x² - 4xy + y² )

→ Simplify

9y² - 4x² + 4xy - y²

→ Simplify again

8y² + 4xy - 4x²

→ Factor

( 4y + 4x ) ( 2y - x )

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4 years ago
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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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10 Oranges are equal to $1 so your answer is $6 For 5 Dozen Oranges 

Correct me if im wrong 
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3 years ago
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