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Svet_ta [14]
3 years ago
12

153 is 0.9% of what number? Tell which equivalent ratios you used to find the solution

Mathematics
2 answers:
Sholpan [36]3 years ago
6 0

Answer:

153 is 0.9% of 17000.

We used this equivalent ratios :

\frac{153}{0.9}=\frac{x}{100}

Step-by-step explanation:

Given that 153 is 0.9% of a number, we denote this number as ''x''.

Also, we know that exists a linear relationship between the number and the percentage, and this linear relationship is a direct proportional relationship.Meaning that a higher number indicates a higher percentage and also a lower number indicates a lower percentage.

We know that the number ''x'' will be 100% of the number. Using this following equivalent ratios :

\frac{153}{0.9}=\frac{x}{100}

Solving for ''x'' :

\frac{153}{0.9}=\frac{x}{100}\\x=\frac{(153).(100)}{0.9}=17000

We find that If 153 is 0.9% of a number, the 100% of the number is x = 17000

being 17000 the number.

Naddik [55]3 years ago
3 0
0.9% / 100% = 0.009
= 9/1000

equivalent ratio:
9/1000 = 153/x

cross multiply
9x = 153,000
x = 153,000/9
x = 17,000

153/17,000 = 0.009
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3 x {(300 - 70 ÷ 5) - [3 x 23 - (8 - 2 x 3)]}<br><br> A.657<br> B.2433<br> C. -843
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3 years ago
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3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

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The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
3 years ago
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