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3 years ago

Which set represents the same relation as the graph below? A B C D

Mathematics

2 answers:

eimsori [14]3 years ago

8 0

Answer:

B. {( -1,-2 ), ( -3,-2 ), ( -5,4 ), ( 2,0 ), ( 3,3 ), ( 4,5 ), ( 6,-4 )}

Step-by-step explanation:

We are given the graph showing the points of a relation.

According to the graph, we see that, the given points of the relation are:

( -1,-2 ), ( -3,-2 ), ( -5,4 ), ( 2,0 ), ( 3,3 ), ( 4,5 ) and ( 6,-4 ).

As, we see that there are 7 points in the relation.

So, option C and D are not correct as they have 5 and 6 points respectively.

Also, option A is wrong as it contains different set of points.

Hence, we get that option B is correct.

That is the set representing the graphed relation is {( -1,-2 ), ( -3,-2 ), ( -5,4 ), ( 2,0 ), ( 3,3 ), ( 4,5 ), ( 6,-4 )}

Elena-2011 [213]3 years ago

7 0

Answer:

Option B

Step-by-step explanation:

The relation between two sets will be a subset of product set AxB

If represnted in ordered pair, x will be an element form A and y from set B.

Keeping this into mind, we must have the relation as (x,y) as ordered pair

WE see from the graph the points given are all in the option B

Hence option B is right

Option A is not right because first point (4,-5) is not appearing in the graph

OPtion C is not right because first point (-5,4) is in graph but (-3,-1) is not marked in the graph

Option D is not right because (4,-5) the first point itself is not in the graph

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3 years ago

3. expand the binomial, (x^2-y^2)^3<br> 4. find the fourth term of (a-b^2)^5

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4 years ago

Read 2 more answers

Which is greater or equal to 25,365 cm or 30m

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3 years ago

A country's population in 1991 was 231 million. In 1999 it was 233 million. Estimate the population in 2003 using the exponentia

Stolb23 [73]

Remark

This problem is done in 2 steps. The first step determines k and the second step is your answer.

Determining K

P = 233 million

A = 231 million

k = ??

t = 1999 - 1991 = 8 years.

Solution

P = Ae^(kt)

233 = 231 * e ^(kt) Divide by 231

233/231 = e^(k8) Do the division

1.008658 = e^(k8) Take the log of both sides.

ln(1.008658) = k8 * ln(e) You are in natural logs. Ln(e) = 1; kt can be brought down and made into a result that is multiplied by ln(e)

ln(1.008658) = 8k Take the ln of 1.008 ...

0.008621 = 8k Divide by 8

k = 0.008621 / 8

k = 0.0011 rounded, but a more accurate number is in the storage area of the calculator.

Now to get the second part.

P = ??

A = 231

k = 0.0011

t = 12

P = 231 * e^(0.0011*12)

P = 231 * e^(0.012931114) using the stored value of M

P = 231 * 1.013015083

P = 234.006 which rounded to the closest million is 234 million

Answer 234 million.

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4 years ago