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sweet-ann [11.9K]
1 year ago
5

Here are yesterday's high temperatures (in Fahrenheit) in 12 U.S. cities. 48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80 Notice

that the temperatures are ordered from least to greatest. Give the five-number summary and the interquartile range for the data set. Five-number summary
Minimum:
Lower quartile:
Median:
Upper quartile:
Maximum:
Interquartile range:
Mathematics
1 answer:
Aleksandr [31]1 year ago
4 0

The five number summary and interquartile range for the data-set is given by:

  • Minimum: 48
  • Lower quartile: 54.
  • Median: 63.5.
  • Upper quartile: 74
  • Maximum: 80.
  • Interquartile range: 20

<h3>What are the median and the quartiles of a data-set?</h3>

  • The median of the data-set separates the bottom half from the upper half, that is, it is the 50th percentile.
  • The first quartile is the median of the first half of the data-set.
  • The third quartile is the median of the second half of the data-set.

In this problem, we have that:

  • The minimum value is the smallest value, of 48.
  • The maximum value is the smallest value, of 80.
  • The data-set has even cardinality, hence the median is the mean of the middle elements, which are 63 and 64, hence the median is of 63.5.
  • The first quartile is the median of the five elements of the first half, hence it is of 54.
  • The third quartile is the median of the five elements of the second half, hence it is of 74.
  • The IQR is the difference between the quartiles, hence 74 - 54 = 20.

More can be learned about five number summaries at brainly.com/question/17110151

#SPJ1

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Answer:

a). 32000

b). T_{t}=500\times 4^{t}

c). 1259

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Sum of the bacterial population after t hours will be represented by

T_{n}=ar^{n}

Where a = population at the start

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n = time or duration of the growth in one hour

a). Population of 500 bacteria gets doubled after half an hour.

Or gets 4 times after an hour

This sequence will have a common ratio r = 4

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Therefore, population of the bacteria after 3 hours will be

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T_{t}=500\times 4^{t}

c). We have to calculate the population after 40 minutes.

That means duration 't' = 40 minutes of \frac{2}{3} hours

By the formula,

T_{\frac{2}{3}}=500\times 4^{\frac{2}{3}}

T_{\frac{2}{3}}=1259.92 ≈ 1259

Therefore, number of bacteria after 40 minutes will be 1259.

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ANSWER

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EXPLANATION

From the question we have that,

Nadir saves $1 the first day of a month, $2 the second day, $4 the third day, and so on.

This forms a geometric sequence,

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The first term of this sequence is

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