Depends on its<span> mass and </span>its<span> speed.</span>
When car is at the top of the hill its whole energy is stored in the form of gravitational potential energy
so when height of the car becomes half then its potential energy is given as
so final potential energy when car falls down by half of the height will become half of the initial potential energy
So it is U = 50 MJ after falling down
Now by energy conservation we can say that final potential energy + final Kinetic energy must be equal to the initial potential energy of the car
So here at half of the height kinetic energy of car = 100 - 50 = 50 MJ
so we can say at this point magnitude of potential energy and kinetic energy will be same
<em>A. the same as the potential energy at that point.</em>
The slope of the line on a velocityversus time graph is equal to the acceleration of the object. If the object is moving with an acceleration of +4 m/s/s (i.e., changing its velocity by 4 m/s per second), then the slope of the line will be +4 m/s/s.
3.13x10 to the ninth power
Answer:
74.55Hp
Explanation:
Hello! To solve this problem we must do the following 3 steps.
1. Find the ideal power using the equation to find the power W = mgV
W=mgV
where
M=mass of elevator=1700kg
g=gravity=9.81m/S^2
V=speed=3m/S
W=(1700kg)(9.81m/S^2)(3m/s)=50031W
2.
Now as the problem indicates that 10% of energy is lost in the mechanical system, we divide the power found in the previous step by 90%
3.
finally we convert units from W to hp.
the minimum output power rating in HP of the motor that meets the requirement is 74.55Hp