All categories

2 years ago

8.

1 answer:

4 0

Based on the nature of reflection of light from surfaces, smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

<h3>What is reflection of light waves?</h3>

Reflection of light waves refers tobtye bouncing back of light waves when they hit a shiny surface.

Depending on the nature of the surface, reflection of light waves can either be regular if diffuse.

Smooth surfaces produce regular reflection while rough surfaces produce diffuse reflection.

Based on the properties of reflection:

A microscopic view of a sheet of paper shows that the surface is rough, thus it would produce diffuse reflection.
Rough pages are easier to read from than smooth and glossy surfaces because they produce diffuse reflection while reading off smooth surface causes a glare due to intense regular reflection
A wet road appears darker because more light passes through and it reflects less light and looks darker
diffuse reflection do not all pass through the principal focus, thus an image is not formed off a rough surface

Therefore, it can be concluded that the rough surfaces produce diffuse reflection while smooth and glossy surfaces produce regular reflection.

Learn more about reflection at: brainly.com/question/377660

You might be interested in

How much force is needed to accelerate a bicycle and rider with a total mass of 80 kg at a rate of 2.0 m/s2?

snow_tiger [21]

If I am not mistaken I think it is C. 320 N

5 0

4 years ago

Read 2 more answers

n isolated charged soap bubble of radius R0=7.45 cmR0=7.45 cm is at a potential of V0=307.0 volts.V0=307.0 volts. If the bubble

Gnesinka [82]

Complete Question

An isolated charged soap bubble of radius R0 = 7.45 cm is at a potential of V0=307.0 volts. V0=307.0 volts. If the bubble shrinks to a radius that is 19.0%19.0% of the initial radius, by how much does its electrostatic potential energy ????U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble r

Answer:

The difference is $U_f -U_i = 16 *10^{-7} J$

Explanation:

From the question we are told that

The radius of the soap bubble is $R_o = 7.45 \ cm = \frac{7.45}{100} = 0.0745 \ m$

The potential of the soap bubble is $V_1 =307.0 V$

The new radius of the soap bubble is $R_1 = 0.19 * 7.45=1.4155\ cm = 0.014155 \ m$

The initial electric potential is mathematically represented as

$U_i = \frac{V_1^2 R_o }{2k }$

The final electric potential is mathematically represented as

$U_f = \frac{V_2^2 R_1 }{2k }$

The initial potential is mathematically represented as

$V_1 = \frac{kQ}{R_o}$

The final potential is mathematically represented as

$V_2 = \frac{kQ}{R_1}$

Now

$\frac{V_2}{V_1} = \frac{R_o}{R_1}$

substituting values

$\frac{V_2}{V_1} = \frac{7.45}{1.4155} = \frac{1}{0.19}$

=> $V_2 = \frac{V_1}{0.19}$

$U_f = \frac{V_1^2 R_2 }{2k * 0.19^2}$

Therefore

$U_f -U_i = \frac{V_1^2 R_2 }{2k * 0.19^2} - \frac{V_1^2 R_o }{2k }$

$U_f -U_i = \frac{V_1^2}{2k} [\frac{ R_1 }{ * 0.19^2} - R_o]$

where k is the coulomb's constant with value $9*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.$

substituting values

$U_f -U_i = \frac{307^2}{9 * 10^{9}} [\frac{ 0.014155 }{ 0.19^2} - 0.0745]$

$U_f -U_i = 16 *10^{-7} J$

8 0

3 years ago

What chemicals does the body produce to keep neutral pH?

AleksandrR [38]

The body produces Buffers that can neutralize acids

6 0

3 years ago

9) An electrical appliance has a resistance of 25 N. When this electrical ap-

Neko [114]

(C)

Explanation:

From Ohm's law,

V = IR

Solving for I,

I = V/R

= (230 V)/(25 ohms)

= 9.2 A

6 0

3 years ago

The elevator accelerates upward (in the positive direction) from rest at a rate of 1.95 m/s2 for 2.15 s. Calculate the tension i

sammy [17]

The mass is missing. The mass of the elevator is 1650 kg.

Answer:

The tension in the cable is 19387.5 N.

Explanation:

Given:

Initial velocity of the elevator (u) = 0 m/s

Acceleration in the upward direction (a) = 1.95 m/s²

Time taken by the elevator (t) = 2.15 s

Mass of the elevator and persons (m) = 1650 kg

Let the tension in the cable wire be 'T' Newtons.

Now, there are 2 forces acting in the vertical direction. One is tension in the upward direction and the other the weight of the elevator in the downward direction.

As the elevator is accelerating upward, the net force acts in the upward direction.

So, net force on the elevator is given as:

$F_{net}=T-mg$

Now, from Newton's second law, net force equals mass times acceleration.

$F_{net}=ma\\\\T-mg=ma\\\\T=m(g+a)$

Plug in the given values and solve for 'T'. This gives,

$T=1650\ kg(9.8+1.95)\ m/s^2\\\\T=1650\times11.75\ N\\\\T=19387.5\ N$

Therefore, the tension in the cable is 19387.5 N.

3 0

4 years ago