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lina2011 [118]
1 year ago
3

Make p the subjet in 2/r+1/p=1/q​

Mathematics
1 answer:
scZoUnD [109]1 year ago
4 0

well, let's notice the denominators, hmmm so we can use as the LCD say the expression of "rpq", so, let's multiply both sides by the LCD of "rpq" to do away with the denominators.

\cfrac{2}{r}+\cfrac{1}{p}=\cfrac{1}{q}\implies \stackrel{\textit{multiplying both sides by } ~~ \stackrel{LCD}{rpq}}{rpq\left( \cfrac{2}{r}+\cfrac{1}{p} \right)=rpq\left( \cfrac{1}{q} \right)}\implies 2pq+1rq=1rp \\\\\\ 2pq+rq=rp\implies rq=rp-2pq\implies rq=\stackrel{\textit{common factoring}}{p(r-2q)}\implies \cfrac{rq}{r-2q}=p

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Find the number in the thousand place  

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Step-by-step explanation:

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What did I do wrong?​
NemiM [27]

Answer:

the graph is correct

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3 years ago
En la final de un concurso escolar de
Sati [7]

Usando la distribución hipergeométrica,  la probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es: 0.2 = 20%.

<h3>¿Qué es la fórmula de distribución hipergeométrica?</h3>

La fórmula es:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

C_{n,x} = \frac{n!}{x!(n-x)!}

Los parámetros son:

  • x es el número de éxitos.
  • N es el tamaño de la población.
  • n es el tamaño de la muestra.
  • k es el número total de resultados deseados.

Los valores de los parámetros son:

N = 6, k = 3, n = 2.

La probabilidad de que los alumnos del colegio A obtengan los dos premios (no hay empates), es P(X = 2), por eso:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,6,2,3) = \frac{C_{3,2}C_{3,0}}{C_{6,2}} = 0.2

Puede-se aprender más a cerca de la distribución hipergeométrica en brainly.com/question/24826394

#SPJ1

4 0
2 years ago
I don't under stand what is wrong.
MAXImum [283]

Answer:

In the first step, there is an issue when distributing the -3 to the terms inside of the parentheses. When multiplying the -3 to the -5, you would get an answer of +15, not -15.

The full correct process is:

(4m + 9) - 3(2m - 5) = 4m + 9 - 6m + 15

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4 0
3 years ago
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