If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
Given that a number plate can be formed using 2 alphabets which must come in increasing order.
We are required to find the number of plates that can be formed.
Number of total alphabets=26.
The number of plates will be equal to the number of ways in which two alphabets can be arranged.
Combination is the number of ways in which some combinations can be formed. It is expressed as n=n!/r!(n-r)!
Number of license plates=26*25
=26*25
=650 plates
Hence If in a number plate two different alphabets need to be selected then there are 650 such number plates that can be formed in such a way that the alphabets come in increasing order.
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Answer: There are 980 degrees of freedom for the within subjects factor.
Step-by-step explanation:
Since we have given that
Number of groups = 20
Number of participants in each group = 50
So, number of participants in 20 groups is given by
As we know that
Degrees of freedom for the within subjects factor would be
Hence, there are 980 degrees of freedom for the within subjects factor.
Answer:
sin (x) ≥ 0, between 0° and 180° or 0 and π,
sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6
Step-by-step explanation:
This is how I would do it. Subtract sin(x) from both sides
2 - sin(x) ≥ 0 , then factor out sin(x)
sin(x) [2 sin(x) - 1] ≥0, then set each factor ≥ 0
sin(x) ≥ 0 and 2 sin(x) - 1 ≥ 0
sin (x) ≥ 0, between 0° and 180° or 0 and π
2 sin(x) ≥ 1
sin(x) ≥ 1/2, between 30° and 150° or π/6 and 5π/6