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mafiozo [28]
3 years ago
11

CAN SOMEONE PLEASE HELP I NEED AN EXPLINATION AS WELL ITS DUE IN 30MINS!!!!!!

Mathematics
2 answers:
user100 [1]3 years ago
6 0

give my job back hmph hahaha free point bro 2-x2 iw n lol

GREYUIT [131]3 years ago
4 0

Answer:

your factors are

(x-7) and (2x+3)

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Volume = L x W x V
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The volume of the rectangular prism is 35 ft
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Find the exact value of cos(sin^-1(-5/13))
son4ous [18]

bearing in mind that the hypotenuse is never negative, since it's just a distance unit, so if an angle has a sine ratio of -(5/13) the negative must be the numerator, namely -5/13.

\bf cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right] \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{then we can say that}~\hfill }{sin^{-1}\left( -\cfrac{5}{13} \right)\implies \theta }\qquad \qquad \stackrel{\textit{therefore then}~\hfill }{sin(\theta )=\cfrac{\stackrel{opposite}{-5}}{\stackrel{hypotenuse}{13}}}\impliedby \textit{let's find the \underline{adjacent}}

\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a \qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ \end{cases} \\\\\\ \pm\sqrt{13^2-(-5)^2}=a\implies \pm\sqrt{144}=a\implies \pm 12=a \\\\[-0.35em] ~\dotfill\\\\ cos\left[ sin^{-1}\left( -\cfrac{5}{13} \right) \right]\implies cos(\theta )=\cfrac{\stackrel{adjacent}{\pm 12}}{13}

le's bear in mind that the sine is negative on both the III and IV Quadrants, so both angles are feasible for this sine and therefore, for the III Quadrant we'd have a negative cosine, and for the IV Quadrant we'd have a positive cosine.

8 0
3 years ago
John bought s sponges. There were 10 sponges in each package. Write an expression that shows how many packages John bought.
vekshin1
The expression would be s/10. 
i.e. If you have 20 sponges and 10 sponges are in each package, the number of packages would be 2 because of 20/10.
7 0
4 years ago
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