1. Let c and b represent candy and combo purchases, respectively.
.. amount = 3c +5b
2. amount ≤ 12
.. 3c +5b ≤ 12
3. amount ≥ 12
.. 3c +5b ≥ 12
4. amount = 12
.. 3c +5b = 12
.. (c, b) = (4, 0) . . . . . the only integer solution
They are not all squares because a rhombus has all sides of equal length, but NO right angles. A square is a rhombus WITH right angles.
Hope that clears things up.
The value in this case would be going up. Since .75 being multiplied by an increasing number would only increase, the value must be doing the same.
However, if that t were an exponent, the value would be decreasing. The more a number between 0 and 1 is multiplied by itself, the smaller it gets.
(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4
Answer:
Answer is x>3
Step-by-step explanation:
The last step is: divide -2 to both sides and since the 2 is negative the sign flips so it would be x>3.
Hope my answer has helped you and if not i'm sorry.