Answer:
30
Step-by-step explanation:
d=√(24²+18²)=6√(4²+3²)=6√(16+9)=6√(25)=6×5=30
Answer:
(3.10 x 10^10)
Step-by-step explanation:
Answer:
See below
Step-by-step explanation:
Q7
- g(s) = 2s + 3,
- g(-2) = 2(-2) + 3 = -4 + 3 = -1
Q8
- h(x) = x² - x + 7
- h(4) = 4² - 4 + 7 = 16 + 3 = 19
Q9
Basic channels = $32.50, each premium channel = $4.95
a) <u>Equation:</u>
b) <u>Table:</u>
- p = 0 ⇒ c = 32.50
- p = 1 ⇒ c = 4.95 + 32.50 = 37.45
- p = 2 ⇒ c = 2*4.95 + 32.50 = 42.40
- p = 3 ⇒ c = 3*4.95 + 32.50 = 47.35
- p = 4 ⇒ c = 4*4.95 + 32.50 = 52.30
<em>The graph is attached</em>
Answer:
Step-by-step explanation:
point slope form
y + 6 = -3(x - 4)
point slope to y-intercept
y + 6 = -3x + 12
y = -3x + 6
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
