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Katyanochek1 [597]
2 years ago
11

Find derivative of y= sin x sin 3x​

Mathematics
1 answer:
UkoKoshka [18]2 years ago
6 0

The derivative of y= sin x sin 3x​ is $=3 \cos x-3 \cos 3 x$

<h3>What is a derivative?</h3>
  • Futures contracts, options contracts, and credit default swaps are typical types of derivatives. Beyond this, a sizable number of derivative contracts satisfy the requirements of a wide range of counterparties.

To find the derivative of y= sin x sin 3x​:

$y=3 \sin (x)-\sin (3 x)$

$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$

$y^{\prime}=3(\cos x-\cos 3 x)$

\frac{dx}{dy} =3 cosx - 3 cos x

Differentiate sin 3x using the chain rule

Given y=f^{'} (g(x))*g^{'}←chain rule

y=y=3 sin x-sin 3x

\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)

=3cosx-3cos3x

To learn more about derivatives, refer to

brainly.com/question/23819325

#SPJ9

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