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Katyanochek1 [597]
2 years ago
11

Find derivative of y= sin x sin 3x​

Mathematics
1 answer:
UkoKoshka [18]2 years ago
6 0

The derivative of y= sin x sin 3x​ is $=3 \cos x-3 \cos 3 x$

<h3>What is a derivative?</h3>
  • Futures contracts, options contracts, and credit default swaps are typical types of derivatives. Beyond this, a sizable number of derivative contracts satisfy the requirements of a wide range of counterparties.

To find the derivative of y= sin x sin 3x​:

$y=3 \sin (x)-\sin (3 x)$

$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$

$y^{\prime}=3(\cos x-\cos 3 x)$

\frac{dx}{dy} =3 cosx - 3 cos x

Differentiate sin 3x using the chain rule

Given y=f^{'} (g(x))*g^{'}←chain rule

y=y=3 sin x-sin 3x

\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)

=3cosx-3cos3x

To learn more about derivatives, refer to

brainly.com/question/23819325

#SPJ9

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3 years ago
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one sam
xeze [42]
X = advance 
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x+y=70

30x+15y=1650

--------------------------
  30x+15y=1650    
- x+y=70               (x15) -> 15x+15y=1050
--------------------------
 30x+15y=1650 
-15x+15y=1050
--------------------------
15x=600
x=600/15
x=40


so now u can insert the price of x AKA the price of the advanced ticket to find our the price of the same day ticket. 

x+y=70
so 
 40+ y=70 
y=70-40
y=30


x = advance =40
y= same day =30





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Read 2 more answers
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